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3 years ago

Choose the best estimate of the sum or diffrence.

Mathematics

1 answer:

Elza [17]3 years ago

7 0

A. 5 because if your subtracting your answer isn’t going to get any bigger than the origina

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What would be the critical value for a two-tailed, one-sample t test with 26 degrees of freedom (df = 26) and an alpha level (p

Alika [10]

Answer: The critical value for a two-tailed t-test = 2.056

The critical value for a one-tailed t-test = 1.706

Step-by-step explanation:

Given : Degree of freedom : df= 26

Significance level : $\alpha=0.05$

Using student's t distribution table , the critical value for a two-tailed t-test will be :-

$t_{\alpha/2, df}=t_{0.025,26}=2.056$

The critical value for a two-tailed t-test = 2.056

Again, Using student's t distribution table , the critical value for a one-tailed t-test will be :-

$t_{\alpha, df}=t_{0.05,26}=1.706$

The critical value for a one-tailed t-test = 1.706

6 0

3 years ago

What is the answer someone help please

Maru [420]

166.25 thats the answer

4 0

3 years ago

The Roberts family is shopping for a new vehicle. They are considering a minivan or an SUV. Each vehicle has three models; stand

azamat

I believe the answer is 30.

8 0

3 years ago

Read 2 more answers

DAVID PLZ HELP LAST ONE

Leto [7]

Answer:

1.D

2.c

Step-by-step explanation:

f(m/4)=8(m²/16)-4(m/4)

=m²/2-m

f(-4)=-3(-4)²+5(-4)

=-3(16)-20

=-48-20

=-68

3 0

3 years ago

Read 2 more answers

The sum of three numbers is 8. The third is 9

Ierofanga [76]

Answer:

→ First value is 1

→ Second value is 2

→ Third value is 5

Step-by-step explanation:

• let numbers be x, y and z

${ \tt{z = 8y - 9 - - - (eqn \: 1)}} \\ \\ { \tt{10x = 8y - 7 - - - (eqn \: 2)}} \\ \\ { \tt{x + y + z = 8 - - - (eqn \: 3)}}$

• from eqn 2, make x the subject:

${ \tt{x = \frac{8y - 7}{10} }} \\$

• substitute all variables in eqn 3:

${ \tt{ \frac{8y - 7}{10} + y + 8y - 9 = 8}} \\ \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\ \\ { \tt{98y = 177}} \\ \\ { \boxed{ \tt{ \: y = 1.8}}}$

• find z

${ \tt{z = 8y - 9}} \\ \\ { \tt{z = 8(1.8) - 9}} \\ \\ { \tt{z = 14.4 - 9}} \\ \\ { \boxed{ \tt{ \: z = 5.4 \: }}}$

• find x:

${ \tt{x = \frac{8(1.8) - 7}{10} }} \\ \\ { \tt{x = \frac{7.4}{10} }} \\ \\ { \boxed{ \tt{ \: x = 0.74 \: }}}$

Rounding to nearest value:

${ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{ \rm{z = 5}}}$

7 0

2 years ago