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miss Akunina [59]
3 years ago
9

The end of a hose was resting on the ground, pointing up an angle. Sal measured the path of the water coming out of the hose and

found that it could be modeled using the equation f(x) = –0.3x2 + 2x, where f(x) is the height of the path of the water above the ground, in feet, and x is the horizontal distance of the path of the water from the end of the hose, in feet.
When the water was 4 feet from the end of the hose, what was its height above the ground?
Mathematics
2 answers:
Amanda [17]3 years ago
6 0
Find f(4)
f(4)=-0.3(4^2)+2(4)
f(4)=-0.3(16)+8
f(4)=-4.8+8
f(4)=3.2

3.2ft above the ground
Travka [436]3 years ago
4 0

Answer:

3.2 feet


Step-by-step explanation:

The equation  f(x)=-0.3x^{2}+2x  shows the height of water [f(x)] and horizontal distance [x].

<em>Given the </em><em>horizontal distance is 4 feet</em><em>, they want to know the height.</em>


<em>Simply put 4 in x of the equation and solve for f(x). So,</em>

<em>f(x)=-0.3(4)^{2}+2(4)\\f(x)=3.2</em>

So, the height of the water was 3.2 feet above the ground.

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Answer:

Part 1) FG=4.4\ units

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Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

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step 2

Find the measure of length side EF

In the right triangle EFG

we know that

cos(27^o)=\frac{EF}{FG} ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

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Answer:

There's no answer choices but I can give you an example.  

Step-by-step explanation:

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