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3 years ago

HELPPPPPPPPP please fast

Mathematics

2 answers:

gtnhenbr [62]3 years ago

5 0

Answer:

B. 1

Step-by-step explanation:

I used a calculator

Misha Larkins [42]3 years ago

4 0

Answer:

b.1

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Four runners start at the same point; Lin, Elena, Diego, Andre. For each runner write a multiplication equation that describes t

Helen [10]

Answers:

Lin's finish point is at 205 meters

Elena's velocity is 8.92 meters per second

Diego's finish point is at -259.2 meters or 259 meters behind the start

Andre's velocity is -8.14 meters per second

I hope this helps <3

6 0

2 years ago

What is the answer to this

Sphinxa [80]

X= 3/9 is the answer!!

7 0

3 years ago

What are the values of x and y?

Ede4ka [16]

Step-by-step explanation:

In figure:

∠PRT+∠RTP+∠TPR=180

(angle sum property of triangle)

⇒x+(180

−∠RTQ)+60

=180

(linear pair)

⇒x+(180

−97

)+60

=180

⇒x=31

Now, ∠PRT+∠TRQ+∠QRS=180

(angle of straight line)

⇒x+48

+y=180

⇒31

+48

+y=180

⇒y=101

3 0

2 years ago

Lella will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $46 and costs an ad

Helen [10]

The plans cost the same at 125 miles. the cost is $63.50

6 0

2 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago