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nikdorinn [45]
3 years ago
6

Which procedure(s) decrease(s) the random error of a measurement: (1) taking the average of more measurements: (2) calibrating t

he instrument; (3) taking fewer measurements? Explain
Chemistry
1 answer:
Fiesta28 [93]3 years ago
8 0

Answer: OPTION * 1

Explanation:

Random error caused by factor which varies from one experiment to another.

And it can be minimised by repeating the experiments and by taking average of all experiments.

Example , we will repeat the titration to get accurate value.

Calibration of instrument comes under determinate errors.

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How many grams of hno3 would you need to prepare 5.5 l of this solution
k0ka [10]

8305 grams of HNO3 would be needed to prepare 5.5L of a solution. Details on how to calculate mass is found below.

<h3>How to calculate mass?</h3>

The mass of a substance in a solution can be calculated using the following formula:

Density = mass ÷ volume

According to this question, 5.5L of a HNO3 solution is given.

Density of HNO3 is 1.51 g/cm³

Volume of HNO3 = 5500mL

1.51 = mass/5500

mass = 8305g

Therefore, 8305 grams of HNO3 would be needed to prepare 5.5L of a solution.

Learn more about mass at: brainly.com/question/19694949

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2 years ago
Which of these is an appropriate instrument to measure mass?
iris [78.8K]

Answer: Balance

Explanation:

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