Answer:
18.7887 g of NaCl
Explanation:
<em>The question reads - How many grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2?</em>
Let us start by writing out the balanced equation of the reaction:
Na + Cl2 ---> NaCl2
1 mole, each of Na and Cl2 is required to produce 1 mole of NaCl.
mole = mass/molar mass
Therefore
18 g of Na = 18/23 = 0.7826 mole
23 g of Cl2 = 23/71 = 0.3239 mole
In this case, the Na is in excess and the Cl2 becomes the limiting reagent. Hence
0.3239 mole of Cl2 will react with 0.3239 mole of Na to yield 0.3239 mole of NaCl.
mass of 0.3239 mole NaCl = 0.3239 x 58 = 18.7887 g
<u>Hence, 18.7887 grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2.</u>
The molar mass of the following compounds in two decimal places are as follows:
- NH3: 17.04 g/mol
- Mg(OH)2: 58.33 g/mol
- Fe2O3: 159.70 g/mol
<h3>MOLAR MASS:</h3>
The molar mass of a compound is the sum of all the atomic masses of the elements that constitutes the compound.
According to this question, three compounds were given as follows: NH3, Mg(OH)2 and Fe2O3.
The atomic mass of the elements in this compounds are as follows:
- N = 14
- H = 1
- Mg = 24
- O = 16
- Fe = 56
- The molar mass of NH3 = 14 + 3 = 17g/mol
- The molar mass of Mg(OH)2 = 24 + 32 + 2 = 58g/mol
- The molar mass of Fe2O3 = 56(2) + 16(3) = 160g/mol
Learn more about molar mass at: brainly.com/question/12127540
Answer:
42 millions of single cells
Answer:
0.272 mol
Explanation:
∆Tb = m × Kb
∆Tb = 85.2°C - 78.4°C = 6.8°C
Kb = 1.22°C/m
mass of ethanol = 48.80 g = 48.80/1000 = 0.0488 kg
Let the moles of non-ionizing solute be y
m (molality) = y/0.0488
6.8 = y/0.0488 × 1.22
y = 6.8×0.0488/1.22 = 0.272 mol