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3 years ago

Why is a phenol more acidic than a regular alcohol? Group of answer choices

Chemistry

1 answer:

Aleks [24]3 years ago

3 0

Answer:

a.Phenols have the ability to spread out the negative charge that forms.

Explanation:

This happens because of the aromatic ring the phenols have. When loosing the proton, the anion formed have different resonance isomers due to the double bonds in the aromatic ring. This resonance makes the anion more stable and prevents the reaction going backwards.

On the other hand, regular alcohol doesn't have resonace and the reaction of loosing the proton goes leftward and righward: is in equilibrium.

That equilibrium decreases the acidity of the alcohol.

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Which statement is true in comparison to a weak acid, a strong acid

Allushta [10]

Answer: Strong acid vs weak acid

Strong acids and strong bases refer to species that completely dissociate to form ions in solution.

Explanation: By contrast, weak acids and bases ionize only partially, and the ionization reaction is reversible. Thus, weak acid and base solutions contain multiple charged and uncharged species in dynamic equilibrium.

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3 years ago

In naming the compound PCl5, the prefix used with the second element is ____________________.

Oksanka [162]

Answer:

$\boxed {\boxed {\sf Hepta}}$

Explanation:

We are given the formula:

$PCl_5$

This is a molecular formula, because it contains nonmetals.

1. Name the first element

The first element is phosphorous (P). Since this is the first element and there is only one, we don't need a prefix.

Phosphorous

2. Second element

The second element is chlorine (Cl). It has a subscript of 5, so we must add the prefix of <u>hepta</u>-.

Phosphorous heptachlorine

Add the ending of -ide.

Phosphorous heptachloride

The prefix used for the second element is hepta. The compound name is phosphorous heptachloride.

6 0

3 years ago

Draw the alkyne formed when 1,1-dichloro-4-methylpentane is treated with an excess of a strong base such as sodium amide. (give

alisha [4.7K]

Co2 is correct buddy

4 0

4 years ago

Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1

anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

$m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g$

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

$m_{O_2}=8.65g-8.00g=0.65g$

Learn more:

3 0

2 years ago

G an aqueous solution contains 0.10 m naoh. the solution is ________. an aqueous solution contains 0.10 m naoh. the solution is

Bad White [126]

Answer is "basic".

NaOH is basic solution and it is a colorless solution. Due to the concentraion is 0.1 M, the solution contains 0.1 M of OH⁻ ions because NaOH fully dissociates into its ions as OH⁻ and Na⁺ in water.

NaOH → OH⁻ + Na⁺

pOH = -log[OH⁻]
= -log(0.1)
= 1
pH = 14 - pOH
= 14 - 1
= 13

Hence, pH of this G solution is 13 which is highly basic.

5 0

3 years ago