Answer:
class Main {
public static void main(String[] args) {
char arr[] = {'T','E','D','R','W','B','S','V','A'};
int n = arr.length;
System.out.println("Selection Sort:");
System.out.println("Iteration\tArray\tComparisons");
long comp1 = selectionSort(arr);
System.out.println("Total comparisons: "+comp1);
System.out.println("\nInsertion Sort:");
System.out.println("Iteration\tArray\tComparisons");
long comp2 = insertionSort(arr);
System.out.println("Total Comparisons: "+comp2);
System.out.println("\nOverall Total Comparisons: "+(comp1+comp2));
}
static long selectionSort(char arr[]) {
// applies selection sort for n/2 elements
// returns number of comparisons
int n = arr.length;
long comparisons = 0;
// One by one move boundary of unsorted subarray
for (int i = n-1; i>=n-n/2; i--) {
// Find the minimum element in unsorted array
int max_idx = i;
for (int j = i-1; j>=0; j--) {
// there is a comparison everytime this loop returns
comparisons++;
if (arr[j] > arr[max_idx])
max_idx = j;
}
// Swap the found minimum element with the first
// element
char temp = arr[max_idx];
arr[max_idx] = arr[i];
arr[i] = temp;
System.out.print(n-1-i+"\t");
printArray(arr);
System.out.println("\t"+comparisons);
}
return comparisons;
}
static long insertionSort(char arr[]) {
// applies insertion sort for n/2 elements
// returns number of comparisons
int n = arr.length;
n = n-n/2; // sort only the first n/2 elements
long comparisons = 0;
for (int i = 1; i < n; ++i) {
char key = arr[i];
int j = i - 1;
/* Move elements of arr[0..i-1], that are
greater than key, to one position ahead
of their current position */
while (j >= 0) {
// there is a comparison everytime this loop runs
comparisons++;
if (arr[j] > key) {
arr[j + 1] = arr[j];
} else {
break;
}
j--;
}
arr[j + 1] = key;
System.out.print(i-1+"\t");
printArray(arr);
System.out.println("\t"+comparisons);
}
return comparisons;
}
static void printArray(char arr[]) {
for (int i=0; i<arr.length; i++)
System.out.print(arr[i]+" ");
}
}
Explanation:
Explanation is in the answer.
