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dolphi86 [110]
3 years ago
11

Does this graph show a function?

Mathematics
2 answers:
Vsevolod [243]3 years ago
8 0

Answer:

Yes it is a function.

Step-by-step explanation:

B is my answer.

slega [8]3 years ago
5 0

Answer:

B. Yes, the graph passes the vertical line test

Step-by-step explanation:

Your welcome

Hope this helps :)

- massmaster34

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Find the volume of this figure to the nearest whole number. Use 3.14 for pi.
sukhopar [10]

Answer:

≈ 1800 mm³

Step-by-step explanation:

Volume of the figure above will be given by the formula

Cross section area × length

In this case;

Cross section area will be;

Area of the square + area of the two semi circles

12× 12 + 2(3.14 × 6 ×6/2)

= 144 + 3.14 ×36

= 257.04 mm²

Volume = Cross section area × Length

             = 257.04 × 7

             = 1799.28 mm³

           <u> ≈ 1800 mm³</u>

3 0
3 years ago
Whats this answer i need it fast uwu
IrinaVladis [17]
Find slope (y2-y1)/(x2-x1)
Pick points: (1,10) , (2,8)
(8-10)/(2-1) = -2/1 = -2
Y = -2x + b
10 = -2 + b, b = 12
It would be the first response
12 = initial while -2 is rate of change
3 0
2 years ago
Simplify the expression (7a5b6)4 . Please help
8_murik_8 [283]

Answer:

28a 20b 24

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu
ra1l [238]

The imaginary unit i belongs to the set of complex numbers, denoted by \mathbb C. These numbers take the form a+bi, where a,b are any real numbers.

The set of real numbers, \mathbb R, is a subset of \mathbb C, where each number in \mathbb R can be obtained by taking b=0 and letting a be any real number.

But any number in \mathbb C with non-zero imaginary part is not a real number. This includes i.

  • "is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because 2=2+0i.

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising i to the i-th power. Since i=e^{i\pi/2}, we have

i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079

3 0
3 years ago
Can someone please explain with answer?
ira [324]

Using: A^2+b^2=c^2

A&b= (√10)^2=10

10+10=c^2

20=c^2

(take the square root of 20)

c=2√5

Your answer is D

7 0
3 years ago
Read 2 more answers
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