Answer:
1250 g=1.25 Kg
Explanation:
We are given that Jason has five fishes of equally massed lead fish weights.
Weigh of each fish =250 grams
We have to find the value of total mass of the five lead fishing weights
Total number of fishes=5
In order to find the total mass we will use unitary method
Total mass is obtained by multiplying the total number of fishes with weight of one fish
Total mass=
Total mass of five fishes=1250 g
1 kg =1000g
Then 1250 g=
Hence, total mass of five lead fishing weights=1250 g=1.25 Kg
Answer:
An atom's electronegativity gets higher as you move up in the periodic table. Thus, the atoms in the top right have the highest electronegativities and the atoms in the bottom left have the lowest ones.
Answer:
1128.
Explanation:
The dominant taster phenotype is 1482.
The recessive taster phenotype = 2400 – 1482 = 918
.
Recessive phenotypes = 2400 – 1482 = 918
The recessive phenotype frequency = q² = 918 / 2400 = 0.38.
the recessive allele frequency q = √0.38 = 0.62.
The dominant allele frequency, p = 1-q = 1- 0.62 = 0.38
The heterozygous frequency = 2pq = 2 ×0.38 × 0.62 = 0.47
.
The heterozygous individual in the population = 0.47 × 2400 = 1128.
Thus, the answer is 1128.
Proteins of smaller molecular size may be reabsorbed from the glomerular filtrate by the specific transport process of endocytosis.
<h3>What do you mean by Glomerular filtrate?</h3>
The Glomerular filtrate may be defined as the liquid in the lumen of the Bowman's capsule of the nephron that has been purified from the capillaries of the glomerulus.
The small molecular size proteins may be absorbed from the glomerular filtrate by receptor-mediated endocytosis. Then moved into the endosomes, and finally to the lysosomes for the degradation.
Therefore, proteins of smaller molecular size may be reabsorbed from the glomerular filtrate by the specific transport process of endocytosis.
To learn more about Nephron, refer to the link:
brainly.com/question/832244
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