Answer:
The correct answer is -
Possible F2 offspring genotypes and phenotypes:
SsLl: normal bristle, normal wing
Ssll: normal bristle, vestigial wing
ssLl: singed bristle, normal wing
ssll: singed bristle, vestigial wing
Explanation:
In this case, the genes 's' and 'L' and genes 'S' and 'l' are linked, they will be passed on to the gamete together.
The cross would be as follows:
F1:
Parents: singed bristles and normal wings x normal bristles and vestigial wings
Genotype: ssLL SSll
Gametes: sL Sl
F1: SsLl ( normal bristles and normal wings )
For F2,
Parents: normal bristles and normal wings x singed bristles and vestigial wings
Genotypes: SsLl ssll
Gametes: SL, Sl, sL, sl
Cross:
SL Sl sL sl
sl SsLl Ssll ssLl ssll
Thus the possible offspring will have -
SsLl: normal bristle, normal wing
Ssll: normal bristle, vestigial wing
ssLl: singed bristle, normal wing
ssll: singed bristle, vestigial wing
