Question

The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.

Answer 1

Answer:

a) 52.8

Explanation:

M1V1 = M2V2

(7.91 M)(x ml) = (2.13 M) (196.1 ml)

(7.91M) (xml) = 417.693 M.ml

x ml = 417.693/ 7.91

x   =  52.8

Answer 2

Answer:

A. 52.8

Explanation:

We make use of the dilution formula to solve this

$M_1\times V_1 =M_2\times V_2$

Where ($M_1$ and $M_2$ are the initial molarity and final molarity and $V_1$ and $V_2$ are  the initial volume and final volume)

Plugging into the values in the formula  

$M_1\times V_1 =M_2\times V_2$

$7.91M \times V_1=2.13M \times 196.1mL$

$V_1=\frac {(2.13M \times 196.1mL)}{7.91M}$

= 52.8 mL is the Answer