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Lostsunrise [7]
3 years ago
11

Describe the appearance of table salt at the macroscopic and atomic levels

Chemistry
1 answer:
Tresset [83]3 years ago
3 0
Table salt is sodium chloride mixed with small<span> amount of </span>potassium iodide (KI)<span>, </span>sodium iodide (NaI)<span> or </span>sodium iodate (NaIO₃)<span>.
Atomic level - sodium chloride (NaCl) has crystal cubic structure (</span>lattice-type arrangement)<span> with ionic bonds. Sodium is cation with charge 1+ and chlorine is an anion with charge 1-.
Macroscopic level - table salt is c</span>olorless crystal, soluble in water with high melting and boiling temperature..
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Rank the following salts in order of decreasing pH of their 0.1 M aqueous solutions.(a) FeCl2, FeCl3, MgCl2, KClO2 .(b) NH4Br, N
Firlakuza [10]

Answer:

a) FeCl2, FeCl3, MgCl2, KClO2.

KClO2 --> K+ + ClO2-; ClO2- will hydrolyse to form HClO +OH-

Mg+2, Fe+2 and Fe+3 ions will form acidic solutions, since theyfom slightly amount of

Mg+2 + 2H2O <-> Mg(OH)2 + 2H+

Fe+2 + 2H2O <-> Fe(OH)2 + 2H+

Fe+3 + 3H2O <-> Fe(OH)3 + 3H+

Therefore;

decreasing pH is high pH to low pH:

KClO2 > MgCl2 > FeCl2 > FeCl3

b) NH4Br, NaBrO2, NaBr, NaClO2.

NH4Br is acidic, forms NH4+ and NH4+ dnates H+ to form NH3 andH+

NaBrO2 is basic, forms Na+ + BrO2- then H2O + BrO2- HBrO2

NABr is neutral, NaClO2 is basics, forms Na+ + ClO2-then H2O + ClO2- HClO2

decreasig pH:

NaClO2 > NaBrO2 > NaBr >NH4Br

Note that HClO2 is stronger acid than HBrO2, therefore, expectmore HBrO2 formation

NaBrO2 > NaClO2 > NaBr >NH4Br

5 0
3 years ago
Why flame tests are not useful for all elements?
Shalnov [3]
<span>Not all elements have strong visible spectra in a flame</span>
3 0
3 years ago
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Consider a solution that is 0.05 M HCl. Your goal is to neutralize 1 L of this solution (i.e. bring the pH to 7). You also have
Ilia_Sergeevich [38]

Answer:

The volume of NaOH required is - 0.01 L

Explanation:

At equivalence point ,

Moles of HCl = Moles of NaOH

Considering :-

Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}

Given  that:

Molarity_{NaOH}=5\ M

Volume_{NaOH}=?\ L

Volume_{HCl}=1\ L

Molarity_{HCl}=0.05\ M

So,  

Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}

0.05\times 1=5\times Volume_{NaOH}

Volume_{NaOH}=\frac{0.05\times 1}{5}=0.01\ L

<u>The volume of NaOH required is - 0.01 L</u>

3 0
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What are eight elements named after towns
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