Solubility,,,,,add water to the mixture,salt will dissolve to form a solution while sand is insoluble,,,,,decant the salt solution as filtrate and remain with sand as residue,,,,,if salt crystals are needed,,,,evaporate the filtrate to dryness.
I am pretty sure the correct answer is C. Water has large heat capacity meaning it can absorb a lot of energy before changing temperature. That helps the body regulate heat since it can be exposed to different environments and experience small temperature changes.
I hope this helps. Let me know if anything is unclear.
Answer:
Equation S= (°C + 117.3)/1.956 °S(25°C) = 72.25°S
Explanation:
To know the difference between the scales, we must initially know the length of our new scale compared to the scale in Celcius degrees, for this we add the absolute value of our melting point and the boiling point | -117.3 ° C | + | 78.3 ° C | = 195.6 ° C
Because our new scale will be divided into 100 equal parts we can know the unit value of each degree ° C concerning degrees ° S. 195.6 / 100 = 1,956 ° C / ° S
For a linear relationship of the scales, the crossing point at ° S = 0.00 is equal to -117.3 ° C. whereby we can clear our equation to know the temperature in degrees Celcius from ° S
°C= -117.3 + °S * 1.956°C/°S
Clearing °S we obtain
°S = (°C + 117.3)/1.956°C/°S
(ii)
In this new scale the temperature of 25°C will be readed as
°S = (25°C+117.3)/1.956°C/°S = 72.25°S
The original concentration is 5.1 × 10⁹ CFU / ml
In order to attain a countable plate, the number of CFU must be present in between 10 and 200 per ml.
Let us take 0.1 ml and dilute it to 1 ml.
This minimizes the concentration to 5.1 × 10⁹ × 10⁻¹ = 5.1 × 10⁸ CFU/ml
In order to minimize the concentration in between 10 and 200, it can be reduced to 5.1 × 10¹
The final concentration = 5.1 × 10¹ CFU/ml
Initial concentration = 5.1 × 10⁹ CFU/ml
Volume of sample with 5.1 × 10¹ CFU = 5.1 × 10¹ CFU × (1 ml / 5.1 × 10⁹ CFU)
= 1.0 × 10⁻⁸ ml
This is the volume to be taken to obtain countable value, 51 CFU.
I think Batteries you can connect a batteries to a circuit and reaction between chericals