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vesna_86 [32]
2 years ago
7

At a cost of $1600/oz, how much would you have to pay for a solid cubic foot of gold?

Chemistry
1 answer:
Alex777 [14]2 years ago
4 0
<h3>You will pay $ 30876800</h3>

We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:

<h3 />

Density of gold = 19298 oz/ft³

Volume of gold = 1 ft³

<h3>Mass of gold =?</h3>

Density = mass /volume

19298 = mass / 1

<h3>Mass of gold = 19298 oz</h3>

Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:

1 oz = $ 1600

Therefore,

19298 oz = 19298 × 1600

19298 oz = $ 30876800

Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800

Learn more: brainly.com/question/15407624

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2 years ago
3.8 liters of sulfur vapor, S8(g), at 921.4°C and 5.87 atm is burned in excess pure oxygen gas to give sulfur dioxide gas measur
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116.5 g of SO₂ are formed

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We convert the 921.4°C to Absolute T° → 921.4°C + 273 = 1194.4 K

5.87 atm . 3.8L = n . 0.082 L.atm/mol.K . 1194.4K

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An egg is placed in a graduated cylinder to determine its volume. The following data are obtained. What is the volume of the egg
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Consider two equal-volume balloons under the same conditions of temperature and pressure. One contains helium, and the other con
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2. Since they have the same number of mole, then they both contain the same number of molecules as explained by Avogadro's hypothesis which states that at the same temperature and pressure, 1 mole of any substance contains 6.02x10^23 molecules or atoms.

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