The perimeter of a rectangle is 60 meters. Its length is 10 meters. What is its width?
1 answer:
Answer:
![\boxed {\tt 20 \ meters}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Ctt%2020%20%5C%20meters%7D)
Step-by-step explanation:
The perimeter of a rectangle can be found using the following formula.
![p= 2l+2w](https://tex.z-dn.net/?f=p%3D%202l%2B2w)
We know the perimeter is 60 meters and the length is 10 meters.
![p=60 \ m](https://tex.z-dn.net/?f=p%3D60%20%5C%20m)
![l= 10 \ m](https://tex.z-dn.net/?f=l%3D%2010%20%5C%20m)
Substitute the values into the formula.
![60 \ m = 2(10 \ m) + 2w](https://tex.z-dn.net/?f=60%20%5C%20m%20%3D%202%2810%20%5C%20m%29%20%2B%202w)
Multiply 2 and 10.
![60 \ m = 20 \ m +2w](https://tex.z-dn.net/?f=60%20%5C%20m%20%3D%2020%20%5C%20m%20%2B2w)
Subtract 20 from both sides of the equation.
![60 \ m - 20 \ m = 20 \ m - 20 \ m +2w](https://tex.z-dn.net/?f=60%20%5C%20m%20-%2020%20%5C%20m%20%3D%2020%20%5C%20m%20-%2020%20%5C%20m%20%2B2w)
![60 \ m - 20 \ m =2w](https://tex.z-dn.net/?f=60%20%5C%20m%20-%2020%20%5C%20m%20%3D2w)
![40 \ m = 2w](https://tex.z-dn.net/?f=40%20%5C%20m%20%3D%202w)
Divide both sides of the equation by 2.
![\frac{40 \ m}{2} =\frac{2w}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B40%20%5C%20m%7D%7B2%7D%20%3D%5Cfrac%7B2w%7D%7B2%7D)
![\frac{40 \ m}{2} =w](https://tex.z-dn.net/?f=%5Cfrac%7B40%20%5C%20m%7D%7B2%7D%20%3Dw)
![20 \ m =w](https://tex.z-dn.net/?f=20%20%5C%20m%20%3Dw)
The width of the rectangle is 20 meters.
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