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Eddi Din [679]
3 years ago
13

Please help! Will give brainliest! Option choices are 2, -5. 11

Mathematics
1 answer:
netineya [11]3 years ago
7 0

Answer:

2

Step-by-step explanation:

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April took out a $600 loan from the bank.At the end of 5 years, she pays back the principle,plus $60 simple interest.What was th
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April took out a loan of $600 and paid it back with simple interest of $60 after 5 years. The formula to calculate interest is  given the principal  and the time   and the interest rate  is . For this problem we have to find the interest rate   given  . To archive that , we can just solve the equation making the interest rate the subject of the formula as shown below,

I= Prt

=> r= I/Pt

=> r= 60/600x5 = 1/50

The interest rate is 1/50 or 0.02 as a decimal. The interest rate is 2% as a percentage.

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3 years ago
Which equation can pair with X- y=-2 to create a consistent and dependent system?
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D is the correct answer to this question
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3 years ago
Point A(1, 4) reflected over the line x = y. What is the coordinate of A’?
alisha [4.7K]

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I believe the answer is (-4,-1)

Step-by-step explanation:

6 0
3 years ago
What is 1 4/7 as a improper fraction
Serhud [2]

Hello there,

To write an improper fraction you will have to divide whole number by denominator than add the numerator...

7 * 1 = 7

7 + 4 = 11

The denominator stays the same...

11/7


Answer: 11/7


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3 0
3 years ago
Read 2 more answers
Someone help with this
elena-14-01-66 [18.8K]

The quadrants are I, II, III, and IV, (meaning 1, 2, 3, and 4). The first quadrant is in the upper right, which has both positive x and positive y values. The second quadrant is the upper left, which has negative x and positive y values. The third quadrant is the lower left, which has both negative x and y values. The fourth quadrant is the lower right, which has positive x and negative y values. Using this knowledge and our positive and negative signs, the following are the answers to questions 1-6.

1) (-4, -2) - Quadrant III, both x and y are negative

2) (0, -7) - This point is actually on the y-axis. The x value is 0 and the y value is -7, so the graph is 7 units down from the origin on the y-axis.

3) (0,0) - This point is the origin, or where the x and y axes cross (the middle of the graph).

4) (6, -9) - This point is in Quadrant IV, because it has a positive x value and a negative y value

5) (3,5) - This point is in Quadrant I, because both the x and y values are positive.

6) (8,0) - This point is on the x-axis. The y-value is zero, so this point is 8 units to the right of the origin between Quadrant I and Quadrant IV.

Using the knowledge presented above, to graph the points given to you in the second part of the problem, first you can figure out what quadrant or part of the graph the point is on. Then, you can count the number of units (squares on the graph) in the right direction (remember that up is positive on the y-axis and down is negative, and to the right is positive on the x-axis and to the left is negative) in order to plot the points. Then, you must connect the points that correspond to the same figure in order to create the figures.

Please comment if you have any questions!

Hope this helps!

7 0
3 years ago
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