Which list contains three equivalent fractions for 2/5

A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 4 cm and diameter of t

docker41 [41]

Answer:

See below ~

Step-by-step explanation:

Things to Find

Volume of Toy
Difference of Volumes in Cube and Toy
Total Surface of Toy

Volume of Toy

Volume of Hemisphere + Volume (Cone)
2/3πr³ + 1/3πr²h
1/3πr² (2r + h)
1/3 x 3.14 x 16 (8 + 4)
1/3 x 50.24 x 12
50.24 x 4
200.96 cm³

Volume of Circumscribing Cube

Edge length is same as diameter
V = (8)³
V = 512 cm³

Difference in Volume

512 - 200.96
311.04 cm³

Slant height of cone

l² = 4² + 4²
l² = 32
l = 4√2 cm = 5.6 cm

Surface Area of Toy

CSA (hemisphere) + CSA (Cone)
2πr² + πrl
πr (2r + l)
3.14 x 4 (8 + 5.6)
12.56 x 13.6
170.8 cm²

3 0

1 year ago

Solve surface area please! Quick it’s due soon

just olya [345]

Answer:

SA = 470 m²

volume = 494 m³

Step-by-step explanation:

Individual areas

Back = 4 x 19 = 76 m²

Top = 5 x 19 = 95 m²

sloped side = 5 x 19 = 95 m²

base = 8 x 19 = 152 m²

end = (4 x 5) + 1/2(3 x 4) = 26 m²

Total SA = 76 + 95 + 95 + 152 + (2 x 26) = 470 m²

Volume

volume = (4 x 5 x 19) + 1/2(3 x 4 x 19) = 494 m³

5 0

2 years ago

The area of the patio is 216 square feet. Write an equation that represents the area of the patio

Hoochie [10]

Answer:

$216=2w \times w$

Step-by-step explanation:

Assuming that the patio is a rectangle, we have

$A= l\times w$

Where $l$ is the length and $w$ is the width.

Now let's assume that the length of the patio is double than the width.

$l=2w$

So, the equation that represents this problem is

$216=2w \times w$

6 0

3 years ago

Write the expression for the Area of the polygon BORT MO 6 A= O A = 6m + mp O A = mp + 1/2(6m) O A = mp + 6p

anyanavicka [17]

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

$A_{sq}=mp$

The area of the triangle is given by the following formula:

$A_t=\frac{bh}{2}$

Where "b" is the base and "h" is its height. Replacing the values:

$A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m$

The total area is the sum of both areas:

$A=A_{sq}+A_t$

replacing the areas:

$A=mp+\frac{1}{2}6m$

7 0

1 year ago

A college job placement office collected data about students’ GPAs and the salaries they earned in their first jobs after gradua

frez [133]

Answer:

X is the GPA

Y is the Salary

Standard deviation of X is 0.4

Standard deviation of Y is 8500

E(X)=2.9

E(Y)=47200

We are given that The correlation between the two variables was r = 0.72

a) $y = a+bx$

$b = \frac{\sum(x_i-\bar{x})(y_i-\bar{y})}{\sum(x_i-\bar{x})^2} = \frac{r \times \sqrt{var(X) \times Var(Y)}}{Var(X)} = \frac{0.72 \times \sqrt{0.4^2 \times 8500^2}}{0.4^2} = 15300$

$a=y-bx = 47200-(15300 \times 29) = 2830$

So, slope = 15300

Intercept = 2830

So, equation : $y = 2830+15300x$

b) Your brother just graduated from that college with a GPA of 3.30. He tells you that based on this model the residual for his pay is -$1880. What salary is he earning?

$y = 2830+15300 \times 3.3 = 53320$

Observed salary = Residual + predicted = -1860+53320 = 51440

c)) What proportion of the variation in salaries is explained by variation in GPA?

The proportion of the variation in salaries is explained by variation in GPA = $r^2 = (0.72)^2 =0.5184$

8 0

3 years ago