How do I solve the equation 18=2/5f
1 answer:
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Answer:
Reactive power is 1.152 VARs
Step-by-step explanation:
We are given that in a parallel circuit,,R=47kΩ and
=50kΩ.
reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.
Current through inductor=milli amps=0.0048 A
Reactive power = (current flowing through inductor)X (Voltage across inductor)
Hence reactive power = 0.0048 X 240=1.152 VARs
Answer:
Step-by-step explanation:
Use the distributive property of equality to multiply and get:
Simplify by combining like terms to get your end result: