The given data is Magnification, M = 15
Length of the tube , L = 16 cm
The focal length of the lens can be calculated by:
M = L/F
Substituting the value, we get:
15 = 16/f
f = 16/15
f = 1.067 cm
Using the equation of magnification we get,
M = v/u
Substituting the values we get:
15 = v/u
v = 15 u
With the help of lens formula, calculate the object distance:
1/f = 1/v + 1/u
Substituting the value we get,
1/1.067 = 1/15u + 1/u
0.937 = 1.067/u
u = 1.13 cm or 1.1 cm.
Hence, the object distance is 1.1 cm.
The correct answer is (b.) an increase in the width of the stem. The increase in the width of the stem could be referred to as the secondary growth of the stem. Whereas the primary growth is the upward growth of the plant.
A manifestation of local blood flow regulation.
Eukaryote cells have a nucleus of course , and also you’ll see that its larger and has a cell membrane .
Answer:
Vacuole. A vacuole is a membrane-bound cell organelle. In animal cells, vacuoles are generally small and help sequester waste products. In plant cells, vacuoles help maintain water balance.
Explanation:
