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3 years ago

10

a quarterback rushed for a gain of 9 yards in the first play of a football game. on the very next play, he was sacked and lost 9

yards. how many total yards did the quarterback gain in the first two plays?

1 answer:

Svetlanka [38]3 years ago

3 0

9 yards total because the quarterback didnt gain any yards during the second play

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You have 5/6 cup of cocoa in your cupboard. A recipe for cookies calls for 2/5 cup of cocoa. How much cocoa would you have left

bixtya [17]

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3 years ago

What is the value of x in the equation -x=2-3x+6

Ahat [919]

-x+3x=2x
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Find the unit vector in the direction of u = (-3,2).

DENIUS [597]

$\bf \textit{unit vector for }(a,b)\implies \left( \cfrac{a}{\sqrt{a^2+b^2}}~~,~~\cfrac{b}{\sqrt{a^2+b^2}} \right)\\\\
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(-3,2)\qquad \stackrel{unit~vector}{\implies }\qquad \left( \cfrac{-3}{\sqrt{(-3)^2+2^2}}~~,~~\cfrac{2}{\sqrt{(-3)^2+2^2}} \right)
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\left( -\cfrac{3}{\sqrt{13}}~~,~~ \cfrac{2}{\sqrt{13}}\right)\\\\
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$\bf \textit{and now let's \underline{rationalize} the denominator for each}
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3 years ago

Factor 64 - P.<br> (8 - x(8 - x)<br> (8 + x (8 - x)<br> (X + 8)(x-8)

muminat

Question:

Factor $64-x^2$

(8 - x)(8 - x)

(8 + x) (8 - x)

(X + 8)(x-8)

Answer:

Option B: $(8+x)(8-x)$ is the factor

Explanation:

Given that the expression is $64-x^2$

We need to find the factor of the given expression.

Let us rewrite the expression as $8^2-x^{2}$

Since the expression is of the form $a^2-b^2$ , let us use the identity $a^2-b^2=(a+b)(a-b)$

where a = 8 and b = x

Substituting the values in the identity, then the expression can be written as

$8^2-x^{2}=(8+x)(8-x)$

Thus, the factor of the expression is $(8+x)(8-x)$

Hence, Option B is the correct answer.

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3 years ago

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Liula [17]

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