Answer:
2.7 kb
Step-by-step explanation:
Total kb = 7.48
Total apps = 2
one app = 4.78
another app = x
> 4.78 + x = 7.48
x = 7.48 – 4.78
= 2.7 kb
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
Answer:
I'm pretty sure it would be 345, just add the two 178 and 167
Answer:
I believe the answer will be around 28
Step-by-step explanation:
Hope this Helped
