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ddd [48]
3 years ago
8

|5x−7| =3 help please

Mathematics
1 answer:
butalik [34]3 years ago
3 0

Answer:

x=2 or x= 4/5

Step-by-step explanation:

Negative case: -(5x-7) = 3  

Multiply

-5x+7 = 3  

Rearrange and Add up

-5x = -4  

Divide both sides by 5  

-x = -(4/5)  

Multiply both sides by (-1)  

x = (4/5)  

 

Then find the positive case: (5x-7) = 3  

Rearrange and Add up

5x = 10  

Divide both sides by 5  

x = 2  

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Parabola Equations - Algebra
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Answer:

h=-\frac{1}{6}x^2+2x

Step-by-step explanation:

The height of the tunnel is modeled by:

h=rx^2+tx

Where r and t are constants.

We know that the maximum height of the tunnel h is 6 meters.

And at ground level, the width is 12 meters.

And we want to determine the equation of the parabola.

First, since this is a quadratic, our maximum height h will occur at the vertex of our equation.

The vertex is given by:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

In our case, we have the function:

h=(r)x^2+(t)x

Hence, a=r; b=t; and c=0.

Therefore, our vertex is:

\Rightarrow -\frac{t}{2r}

Thus, if we substitute this back into our equation, we should get 6 since 6 is the maximum height which is determine by the vertex. In other words:

(6)=r(-\frac{t}{2r})^2+t(-\frac{t}{2r})

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6=r(\frac{t^2}{4r^2})-\frac{t^2}{2r}

Simplify:

6=\frac{t^2}{4r}-\frac{t^2}{2r}

Combine fractions:

6=\frac{t^2}{4r}-\frac{2t^2}{4r}=\frac{-t^2}{4r}

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24r=-t^2

Let's solve for the constant r. Divide both sides by 24. Hence:

r=-\frac{t^2}{24}

Now, we can use our knowledge of the width.

We know that the width is 12 meters at ground level.

Hence, when h=0, the <em>difference of our roots</em> is 12.

So:

0=rx^2+tx

We can factor:

0=x(rx+t)

By the Zero Product Property:

x=0\text{ or } rx+t=0

So, the first zero is 0.

Therefore, the second zero <em>must be 12</em> to ensure that our width is 12.

Let's isolate the second zero. Subtract t from both sides:

rx=-t

Divide both sides by r:

x=-\frac{t}{r}

We know that this zero must be 12. Thus:

12=-\frac{t}{r}

We have previously solved for r. Substitute:

12=-\frac{t}{\frac{-t^2}{24}}

Simplify:

12=\frac{24}{t}

Take the reciprocal of both sides:

\frac{t}{24}=\frac{1}{12}

Multiply both sides by 24. Hence, the value of t is:

t=2

Now, we can find r. r is given by:

r=-\frac{t^2}{24}

By substituting 2 for t, then, we acquire that:

r=-\frac{(2)^2}{24}=-\frac{4}{24}=-\frac{1}{6}

Therefore, for:

h=rx^2+tx

Our equation is:

h=-\frac{1}{6}x^2+2x

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