Answer:
Step-by-step explanation:
Solution by substitution method
3x-4y=8
and 18x-5y=10
Suppose,
3x-4y=8→(1)
and 18x-5y=10→(2)
Taking equation (1), we have
3x-4y=8
⇒3x=4y+8
⇒x=(
4y+8)/
3 →(3)
Putting x=
(4y+8
)/3 in equation (2), we get
18x-5y=10
18(
(4y+8)
/3) -5y=10
⇒24y+48-5y=10
⇒19y+48=10
⇒19y=10-48
⇒19y= -38
⇒y=-
38
/19
⇒y= -2→(4)
Now, Putting y=-2 in equation (3), we get
x=4y+8
x=
(4(-2)+8)
/3
⇒x=
(-8+8)/
3
⇒x=
0/
3
⇒x=0
∴x=0 and y= -2
30 im positive is the answer
I will need the specific book or a photograph to be able to answer this specific question.
Answer:
Step-by-step explanation:
Remark
Triangle BAC is isosceles. It has 2 sides that are both radii of the circle. I assume that C is the center of the circle.
Givens
AC = BC Both of these are radii.
<BCD = 20o Given
<A and <B are equal Both are opposite a radii of the circle
C is the circle's center Assumed otherwise we can't do it.
Solution
<BCD is an exterior angle of Triangle ACB It's on the same straight line as D and A
The sum of 2 remote interior angles = the sum of the exterior angle.
BAC = ABC Stated above
BAC + ABC = 20 Stated right above.
2BAD = 20
BAD = 20/2
BAD = 10
Answer:
1. -15degree C
2. +$27
3. +2010
4. +38
5. +376
6. -$200
7. -3
8. +$150
9. +$41
10. -240
11. +$120
12. -60
Step-by-step explanation:
this is the answer