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2 years ago

I need help on 13. Please someone help me. Don’t put a link. Please help me.

Mathematics

1 answer:

Viktor [21]2 years ago

5 0

Answer and Step-by-step explanation:

How to know if the side lengths can form a triangle:

Add together two of the lowest numbers. If it is greater than the largest number, it can form a triangle.

13. Yes, these side lengths can form a triangle.

-- 4 + 5 = 9.

-- 9 is greater than 7, the largest length.

14. No, these side lengths can't form a triangle.

-- 2 + 3 = 6

-- 6 is equal to 6, not greater than.

15. Yes, these side lengths can form a triangle.

-- 2 + 4 = 6

-- 6 is greater than 5, the largest number.

16. Yes, these side lengths can form a triangle.

-- Don't get confused when you see that there are two side lengths that are the same (it means that this is an isosceles triangle); the rules still apply.

-- 2 + 8 = 10

-- 10 is greater than 8, the largest number.

17. Yes, these side lengths can form a triangle.

-- 5 + 6 = 11

-- 11 is greater than 9, the largest number.

18. Yes, these side lengths can form a triangle.

-- 4 + 5 = 9

-- 9 is greater than 8, the largest number.

I hope this helps!!

#teamtrees #PAW (Plant And Water)

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Canceled cheques are negotiable at the bank for the face value is False

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Light travels at a speed of about 3.0x10^8 meters per second. How far does light travel in 4,500 seconds You Would Get __ E __

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3 years ago

24% of U.S. adults say they are more likely to make purchases during a sales tax holiday. you randomly select 10 adults. find th

neonofarm [45]

Answer:

a) $p(X= 2) = 0.261$

b) P(x>2) = 0.566

c) P(2<x<5) = 0.334

Step-by-step explanation:

Given 24% of U.S. adults say they are more likely to make purchases during a sales tax holiday

Probability 0f U.S. adults say they are more likely to make purchases during a sales tax holiday (p) = 0.24

n = 10

By using Poisson distribution

mean number of make purchases during a sales tax holiday

λ = np = 10 X 0.24 = 2.4

The probability of getting exactly '2'

The probability $p(X= 2) = e^{-\alpha } \frac{\alpha^r }{r! }$

$p(X= 2) = e^{2.4 } \frac{\(2.4)^2 }{2! }$

$p(X= 2) = e^{2.4 } \frac{\(2.4)^2 }{2! }= 0.261$

b) The probability of getting more than '2'

$P(X>2) = 1- {p(x=0)+p(x=1)+p(x=2)}$

$= e^{-2.4 } \frac{(2.4)\^0 }{0! }+ e^{-2.4 } \frac{(2.4)\^1 }{1!}+e^{-2.4 } \frac{(2.4)\^2 }{2!}$

= 0.090 + 0.2177+0.261 = 0.566

P(x>2) = 0.566

c) The probability of getting between two and five

P( 2<x<5) = P(x=3)+p(x=4) = $= e^{-2.4 } \frac{(2.4)\^3 }{3! }+ e^{-2.4 } \frac{(2.4)\^4 }{4!}+$

P(2<x<5) = 0.2090 + 0.125 = 0.334

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3 years ago

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Step-by-step explanation:

liters

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3 years ago

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