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azamat
3 years ago
9

Under what conditions would a rope remain in equilibrium during a tug of war?

Physics
2 answers:
agasfer [191]3 years ago
5 0

B, when the net force is zero

Oksana_A [137]3 years ago
5 0

The rope is in equilibrium when<u><em> either </em></u>there is no force acting on the rope <em>(A)</em> <u><em>or </em></u>when the net force acting on the rope is zero <em>(B)</em><em>.</em>  

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What happens to a path of a light ray parallel to the principal axis, after it passes through a converging
Simora [160]

Answer: The ray that passes through the focal point on the way to the lens will refract and travel parallel to the principal axis. ... All three rays should intersect at exactly the same point.

Explanation: Once these incident rays strike the lens, refract them according to the three rules of refraction for converging lenses.

3 0
3 years ago
A 70 kg student stands on top of a 5.0 m platform diving board . how much gravitational potential energy does the student have?
Marianna [84]

Answer:

a. P.E = 3430Joules.

b. Workdone = 3430Nm

Explanation:

<u>Given the following data;</u>

Mass = 70kg

Distance = 5m

We know that acceleration due to gravity is equal to 9.8m/s²

To find the potential energy;

Potential energy = mgh

P.E = 70*9.8*5

<em>P.E = 3430J</em>

b. To find the workdone;

Workdone = force * distance

But force = mass * acceleration

Force = 70*9.8

Force = 686 Newton.

Workdone = 686 * 5

<em>Workdone = 3430Nm</em>

6 0
3 years ago
Which state of matter is the least compressible
kramer
Incompressible. Compressibility is determine by the amount of space between particles in each state.  
7 0
3 years ago
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A car accelerates at a rate of 13m/s^2[S]. If the car's initial velocity is 120km/h[N]. What will its final velocity be in m/s,
Delvig [45]

Answer:

the final velocity of the car is 59.33 m/s [N]

Explanation:

Given;

acceleration of the car, a = 13 m/s²

initial velocity of the car, u = 120 km/h = 33.33 m/s

duration of the car motion, t = 2 s

The final velocity of the car in the same direction is calculated as follows;

v = u + at

where;

v is the final velocity of the car

v = 33.33 + (13 x 2)

v = 59.33 m/s [N]

Therefore, the final velocity of the car is 59.33 m/s [N]

6 0
3 years ago
How much force is needed to stop a body of mass 10kg​
almond37 [142]

Answer:

Force of <u>1</u><u>0</u><u>0</u><u> </u><u>N</u><u> </u>will be needed.

Explanation:

Force, F = m \times g

g is acceleration due to gravity

m is the mass

F = (10 \times 10) \\ F =  100 \: newtons

3 0
3 years ago
Read 2 more answers
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