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Harlamova29_29 [7]
2 years ago
13

A 12.0-kilogram object is lifted from the ground to a height of 4.00 meters.

Physics
1 answer:
kow [346]2 years ago
4 0

Answer:

3 j

Explanation:

12.0 kilo / 4.00 meters = 3 j

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Pressure of gas is 13.6 cm of hg what does it means​
vlada-n [284]

Explanation:

13 cmHg (centimeters of mercury) is the pressure at the bottom of a column of mercury 13 cm deep.  It is the equivalent of about 17.3 kPa or 2.5 psi.

5 0
3 years ago
Three balls, with masses of 3m,2m and m, are fastened to a massless rod of length L. The rotational inertias about the ledt
Oduvanchick [21]

I = MR^2

The Attempt at a Solution:::

I total = (3M)(0)^2 + (2M)(L/2)^2 + (M)(L)^2

I total = 3ML^2/2

It says the answer is 3ML^2/4 though.

⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔

mark it as brainliest.... ✌✌✌

8 0
2 years ago
L 10. A car with a mass of 2,000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The
garri49 [273]
Centripetal Force, F = mv²/r

Where m = mass in kg, v = velocity in m/s and r = radius of curvature in m.

Centripetal Force, F = 2000 * 25² / 80.    Use your calculator.

                           F = 15 625 N.
3 0
3 years ago
What volume of lead must be fastened underneath it to sink the wood in calm water so that its top is just even with the water le
astraxan [27]
The bouyancy force is:  

Since the wood-lead system is completely submerged, the bouyancy force 

 is FB = ĎwgVl + ĎwgVb, where Ďw is the density of water,Vl 

 is the volume of 

 the piece of lead and Vb is the volume of the wooden block. The weight of the

  combined lead and wooden block is: W = ĎlgVl + ĎbgVb. Since the system is 

 in equilibrium, the bouyancy force must be equal to the total weight: 

 ĎwgVl + ĎwgVb = ĎlgVl + ĎbgVb 

 now we can solve for the volume of lead: 

 ĎwgVl â’ ĎlgVl = ĎbgVb â’ ĎwgVb 

 Vl(Ďw â’ Ďl) = Vb(Ďb â’ Ďw) 

 Vl =   

 Ďbâ’Ďw 

 Ďwâ’Ďl   

 Vb 

 Now we substitute the values for the density of lead Ďl = 11.3 Ă— 103kg/m3  , 

 the density of the wood and the density of water Ďw = 1000kg/m3 

 . We get: 

 Vl =   

 600â’1000 

 1000â’11300 

 (0.6m Ă— 0.25m Ă— 0.08m) = 4.66 Ă— 10â’4m3
4 0
3 years ago
-1
Rom4ik [11]

Answer:

9800 N

Explanation:

applying,

W = Fd.................. Equation 1

Where W = work done by the engine, F = Force exterted to lift the beam, d = distance.

make F the subject of the equation

F = W/d............... Equation 2

From the question,

Given: W = 1421000 J, d = 145 meters.

Substitute these values into equation 2

F = 1421000/145

F = 9800 N

5 0
3 years ago
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