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____ [38]
3 years ago
7

Dos buses escolares transportan cada uno 24 estudiantes. En el primer bus,

Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

los second answer

Step-by-step explanation:

yo soy muy inteligente y no tonta

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If f(x) = -4x - 6, then f (0.3) = ____.
Ivahew [28]

Answer:

-7.2

Step-by-step explanation:

-4(0.3)-6

-1.2-6

-7.2

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The function y=−0.25x+0.55 represents the percent y (in decimal form) of battery power remaining x hours after you turn on a lap
AURORKA [14]
Answer: a is 2.2, b is 0.55
Explanation:
To find the x intercept, put 0 instead of y,
hence,
0=-0.25x+0.55
-0.25x=-0.55
x=2.2
To find y intercept put 0 instead of x,
so,
y=-0.25*0+0.55
y=0+0.55
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One garden has 5 times more raspberry bushes than another garden. After 22 bushes were transplanted from the first garden to the
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One had 55. one had 11
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Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

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3 years ago
He slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -x + 6. What is the point-stopetom
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y-3=2(x+)Step-by-step explanation:

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