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nevsk [136]
3 years ago
5

A. The distance between the towers is 7350 ft, and the angles of elevation are given in the diagram. Find the distance from Towe

r 2 to the plane, to the nearest tenth of a foot.
11099 ft
9448 ft
4894 ft
10032 ft

B. Find the height of the plane from the ground, to the nearest foot. Hint: Use your answer from part a.
8563 ft
9170 ft
10135 ft
11300 ft

Mathematics
2 answers:
melomori [17]3 years ago
7 0
Hello,


A.9448


B.8563

Have a amazing day and Good luck with school!

(I need one more brainliest to reach the expert rank! Thank you!)
Mademuasel [1]3 years ago
4 0
The angle T1PT2 is 65-37=28 degree
use law of sine: sin37/PT2=sin28/7370, PT2=7370*sin37/sin28
Use a calcuator, I got the answer 9448

B. sin65=PA/PT2, PA=PT2*sin65=9448*sin65=8563
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if a student is selected at random find the probability the student is a junior round to the nearest hole percent
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Answer:

=4+6+2+2=14

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Step-by-step explanation:

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5 0
3 years ago
I can't figure out how to do (i + j) x (i x j)for vector calc
Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}

Then, solving the determinant

\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}

In our case,

\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}

Where we used the formula for AxB to calculate ixj.

Finally,

\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}

Thus, (i+j)x(ixj)=i-j

8 0
1 year ago
How to solve y in -(y+9)=10
Allisa [31]

Answer:


Step-by-step explanation:

- (y+9) = 10


Multiply through by -1 gives us


y+9 = -10


Subtract 9 from both sides


y = -19


That's your answer.


If you work it through it satisfies the equation.


That is:


- (-19 +9) = 10


-(-10) = 10


10 = 10


Boo ya!

5 0
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