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oee [108]
3 years ago
6

The area of the red square is 16 ft. The area of the yellow square is 25 ft.

Mathematics
2 answers:
lakkis [162]3 years ago
4 0

Answer:

I believe that the area of the green square is 9ft²

Aliun [14]3 years ago
3 0
Idk if it’s the same picture but the area would be 9ft
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Graph the image of this figure after a dilation with a scale factor of 12centered at the point (−3, 0)
GrogVix [38]

Answer:

bro tbh just use like or

Step-by-step explanation:

its not that deep

6 0
1 year ago
PLZZZZ help as soon as possible
sammy [17]

Answer:

JK = 11

Step-by-step explanation:

JK ≅ JM

where

JK = 3x - 16

JM = 2x - 7

3x - 16 = 2x - 7

group like terms

3x - 2x = 16 - 7

x = 9

<u>plugin x=9 into JK</u>

JK = 3x - 16

JK = 3(9) - 16

JK = 11

6 0
3 years ago
Read 2 more answers
The circumference of a garden is 91.06 feet. what is the diameter of the garden?
Romashka-Z-Leto [24]

Answer:

radius = 14.5 feet

Step-by-step explanation:

91.06 / 3.14 = diameter = 29

radius = 29/2 = 14.5 feet

4 0
2 years ago
Hiiii!
fenix001 [56]

Answer:

100,000,000

Step-by-step explanation:

You can just add up the zeros, if that makes sense.

5 0
3 years ago
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Given that these simultaneous equations
Tatiana [17]

The value of k is(3\sqrt{ 10})/2

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= \sqrt{15-2x^2}...........(eq iii)

Substitute the value of y into eq i

x-(\sqrt{15-2x^2}= k

x- (\sqrt{15} - 2x= k

k= (3\sqrt{ 10})/2

Read more about simultaneous equations here:

brainly.com/question/16863577

#SPJ1

3 0
1 year ago
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