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AnnZ [28]
3 years ago
12

A satellite of mass 4500 kg orbits the Earth in a circular orbit of radius of 7.2 × 106 m (this is above the Earth's atmosphere)

.The mass of the Earth is 6 × 1024 kg. What is the speed of the satellite?
Physics
1 answer:
pantera1 [17]3 years ago
4 0

Answer:

7.457 * 10³ m/s

Explanation:

Parameters given:

Mass of earth, M = 6 * 10^24 kg

Radius of orbit, R = 7.2 * 10^6 m

Orbital velocity is given as:

v = √(GM/R)

Where G = gravitational constant

v = √(6.673 * 10^(-11) * 6 * 10^24)/(7.2 * 10^6)

v = √(5.561 * 10^7)

v = 7.457 * 10³ m/s

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2 years ago
At a given instant an object has an angular velocity. It also has an angular acceleration due to torques that are present. There
katen-ka-za [31]

a) Constant

b) Constant

Explanation:

a)

We can answer this question by using the equivalent of Newton's second law of motion of rotational motion, which can be written as:

\tau_{net} = I \alpha (1)

where

\tau_{net} is the net torque acting on the object in rotation

I is the moment of inertia of the object

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The angular acceleration is the rate of change of the angular velocity, so it can be written as

\alpha = \frac{\Delta \omega}{\Delta t}

where

\Delta \omega is the change in angular velocity

\Delta t is the time interval

So we can rewrite eq.(1) as

\tau_{net}=I\frac{\Delta \omega}{\Delta t}

In this problem, we are told that at a given instant, the object has an angular acceleration due to the presence of torques, so there is a non-zero change in angular velocity.

Then, additional torques are applied, so that the net torque suddenly equal to zero, so:

\tau_{net}=0

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b)

In this second case instead, all the torques are suddenly removed.

This also means that the net torque becomes zero as well:

\tau_{net}=0

Therefore, this means that

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So also in this case, there is no change in angular velocity: this means that the angular velocity of the object will remain constant.

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