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Flauer [41]
3 years ago
8

. A fixed resistor of resistance 3.54  is part of an electrolysis circuit. In an experiment using this circuit, electrolysis wa

s carried out for 30 minutes and 45 s. During the electrolysis, the voltage drop (electrical potential difference) across the resistor was measured to be 442 mV. How much charge flowed during the electrolysis?
Physics
1 answer:
zysi [14]3 years ago
7 0

Answer:

Q = 230.36 C

Explanation:

Given

R = 3.54 Ω

t = 30'45" = (30')*(60"/1') + 45" = 1845 s

V = 442 mV = 442*10⁻³V

Q = ?

We can use Ohm's Law in order to get I as follows

V = I*R   ⇒    I = V / R

⇒    I = 442*10⁻³V / 3.54 Ω = 0.1248 A

Finally we use the formula

I = Q / t     ⇒    Q = I*t = (0.1248 A)(1845 s)

⇒    Q = 230.36 C

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