Answer:
Option D is the correct answer.
Step-by-step explanation:
Let x be the one way distance and t be the time out.
Time taken for back = t-1
We have plane's average speed out was 300 mph and average speed on the way back was 350 mph.
That is

Dividing both equations

Time taken for back = t-1 = 7-1 = 6 hours.
Total time taken = 7 + 6 = 13 hours
Option D is the correct answer.
Answer:
C. 4 times x squared plus 6 times x minus 3 minus 12 over the quantity 2 times x plus 1
Step-by-step explanation:
f(x) = 8x^3 + 16x^2 − 15
g(x) = 2x + 1.
f(x) / g(x) = (8x^3 + 16x^2 − 15) / (2x + 1)
Using long division
Answer:
m=0 (m is the slope)
Step-by-step explanation:
m=y2-y1/x2-x1
m=6-6/1-5
m=0/4
m=0
*Note: If the zero is in the denominator (on the bottom) the slope is undefined (UND).
Answer:
-20 = 0
Step-by-step explanation:
-8 (6 + x) + 4 (2x + 7) = 0
-48 - 8x + 8x + 28 = 0
-20 = 0