G(6)-g(2)/6-2
g(6) = 50
g(2) = 14
50-14/6-2
36/4
=9
Take the derivative with respect to t

the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero

divide by w

we add sin(wt) to both sides

divide both sides by cos(wt)

OR

(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

since 2npi is just the period of cos

substituting our second soultion we get

since 2npi is the period

so the maximum value =

minimum value =
Answer: the answer is 6ft
Step-by-step explanation:
3 times 1 times 2 = 6ft
Answer: 2years, 5 months
Step-by-step explanation:
Principal, P = $6000
Rate, R = 3%
Interest, I = $450
Time, T =?
Simple Interest, I = P x T x R/ 100
making T, subject of formula
T = 100 x I/ P x T
Substituting the values into the equation,
T = 100 x 450/ 6000 x 3
T = 45000/ 18000
T = 2.5years = 2years, 5 months
First lets find -8.2 x 10 = -82 know we find 82^5 which is 82*82*82*82*82
-82*-82=6724 and then 6724*-82= -551368 and then -551368*-82 =45212176 and then 45212176*-82= -3707398432 and finally -3707398432 is our answer i checked the calc to after i did the hard math that took me forever i had some help from the calc and i got this hopefully this helps