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3 years ago

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Find the point P that partitions the line segment AB given the ratio. A (3, 5) B(4, 3) with the ratio 3:1 help im taking a test

1 answer:

Dahasolnce [82]3 years ago

4 0

Answer:

Mena is ka answear btaa biya dak lna plz like kar da na

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denpristay [2]

Answer:

15n=135

Step-by-step explanation:

first, you need to know how much of the total amount is the money needed for soccer balls, to find this you take the amount of a soccer ball and multiple it by the amount of people

14×15=210

then you subtract that from the total amount to get the amount spent on jerseys.

345-210=135

to get the amount of each jersey you take 135 and divide by the amount of people

135÷15=9

4 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

HELPPP!!! <br> Name two triangles that are congruent by ASA?

ASHA 777 [7]

The answer would be the second one, PRQ=VWX because you have to go in the order that gives you angle-side-angle, and that is the only one that includes them in the correct orde.

4 0

3 years ago

Read 2 more answers

How can i use variables to describe real world problems? explain.

Assoli18 [71]

You can use variables such as x & y to represent what you're looking for in the problem or represent information you're given in a real world problem.

7 0

3 years ago

Larissa eats 3/5 of a 1.5-pound bag of goldfish in 5/6 of an hour. If she eats goldfish at a constant rate, how long, in hours,

Anarel [89]

Answer:

it will take Larissa 4 17/27 hours to finish 5lbs of goldfish

Step-by-step explanation:

1.5 pound = 1 1/2 pound equivalent to 3/2 pounds

3/5 of a 1.5-pound

= 3/5 × 3/2 pounds

= 9/10 lbs of goldfish eaten in 5/6 hours

how long, in hours, would it take her to finish a 5-lb box of goldfish?

Find the ratio

9/10 lbs of goldfish : 5/6 hours = 5lbs of goldfish : t hours

9/10 ÷ 5/6 = 5 / t

Solve for t

9/10 × 6/5 = 5 / t

54 / 50 = 5 / t

Cross multiply

54 × t = 50 × 5

54t = 250

Divide both sides by 54

t = 250 / 54

= 4 34/54

= 4 17/27 hours

Therefore, it will take Larissa 4 17/27 hours to finish 5lbs of goldfish

7 0

3 years ago