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3 years ago

Please help me…………….

Mathematics

1 answer:

valina [46]3 years ago

7 0

9514 1404 393

Answer:

54.8 km

Step-by-step explanation:

The sketch and the applicable trig laws cannot be completed until we understand what the question is.

Given:

two boats travel for 3 hours at constant speeds of 22 and 29 km/h from a common point, their straight-line paths separated by an angle of 39°

Find:

the distance between the boats after 3 hours, to the nearest 10th km

Solution:

A diagram of the scenario is attached. The number next to each line is the distance it represents in km.

The distance (c) from B1 to B2 can be found using the law of cosines. We can use the formula ...

c² = a² +b² -2ab·cos(C)

where 'a' and 'b' are the distances from the dock to boat 1 and boat 2, respectively, and C is the angle between their paths as measured at the dock.

The distance of each boat from the dock is its speed in km/h multiplied by the travel time, 3 h.

c² = 66² +87² -2·66·87·cos(39°) ≈ 3000.2558

c ≈ √3000.2558 ≈ 54.77

The boats are about 54.8 km apart after 3 hours.

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Theresa’s computer at home has 1 terabyte of storage. How many more bits of storage does her computer have than the combined bit

posledela

Answer:

Not enough information provided

Step-by-step explanation:

To find the difference between one terabyte and the storage available to the other mediums, we would need to know the storage available to those mediums. They can all have potentially different amounts of storage space, so we have no way to answer that part of the question.

We can however find out how many bits her computer has. There are two lines of thought to follow though. kilo, mega, giga etc each generally note a multiple of 1000 in common terms. In computer tech though, the number 1024, or 2¹⁰, is often used instead.

Starting with the layman's powers of 10, a terabyte is a thousand gigabytes, which in turn is a thousand megabytes, which is a thousand kilobytes, which is a thousand bytes.

That means that a terabyte stores 1 × 10¹² bytes. A byte however is eight bits, giving us 8 × 10¹² bits.

Using the nerdier powers of 2 then, a byte is eight bits, so we'll call that 2³. We then go up by multiples of 2¹⁰. With the same logic above, a terabyte is 2¹⁰ gigabytes, which is 2¹⁰ megabytes, which is 2¹⁰ kilobytes, which is 2¹⁰ bytes. Adding the exponents up, then a terabyte would be 2⁴³ bits

So depending on whether you use the powers of ten or powers of 2 conventions, then a terabyte is either 8 × 10¹² bits, or 2⁴³ bits.

If you want to express the latter as a power of ten for proper scientific notation, then it would be 8.796093022208 × 10¹² - a rather useless way of expressing it, but just to cover all bases.

3 0

3 years ago

Find the diagonal of a rectangular frame which measures 77 in. by 36 in.

quester [9]

Answer:

Diagonal of a rectangular frame = 85 inch

Step-by-step explanation:

Given:

Length of rectangle = 77 inch

Width of rectangle = 36 inch

Find:

Diagonal of a rectangular frame

Computation:

Diagonal of a rectangle = √l² + b²

Diagonal of a rectangular frame = √77² + 36²

Diagonal of a rectangular frame = √5,929 + 1,296

Diagonal of a rectangular frame = √7,225

Diagonal of a rectangular frame = 85 inch

7 0

3 years ago

Find angle abc (2x+14) (x+7)

melisa1 [442]

It's a complementary angle, so just solve for x and subtract the CBD from 90,
First, we have to solve for x.
2x + 14 + x + 7 = 90
Combine like terms
3x + 21 = 90
Balance, subtract 21 from each side.
3x = 69
Divide 3 from each side
x = 23.
So know that we know x is 23, we can go about it 2 ways, subtracting the other angle with 90 or just substituting the variable, I'd just substitute the variable for it so just do 23 + 7. That equals 30, angle ABC = 30.

7 0

3 years ago

Read 2 more answers

Show all steps question is in the photo.

Lady bird [3.3K]

$\\ \sf\longmapsto \sqrt{108x^2y^3}-\sqrt{12x^2y^3}+x\sqrt{75y^3}$

$\\ \sf\longmapsto \sqrt{2\times 2\times 3\times 3\times 3\times x\times x\times y\times y\times y}-\sqrt{2\times 2\times 3\times x\times x\times y\times y\times y}+\sqrt{5\times 5\times 3\times y\times y\times y}$