Answer: h = 17
Step-by-step explanation: As a general rule, if an equation has any fractions in it, try to get rid of those fractions as soon as possible.
The quickest way to get rid of a fraction is to multiply both
sides of the equation by the denominator of the fraction.
So in this problem, we can get rid of the fraction in our
first step by multiplying both sides of the equation by 4.
On the left, the 4's cancel and on the right, 1(4) is 4.
Now we have h - 13 = 4.
Since 13 is being subtracted from <em>h</em>, to get <em>h</em> by itself,
we need to add 13 to both sides of the equation to get h = 17.
Now, we can check our answer by plugging 17 back
into the original equation shown below in italics.



+
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equals

.
First, simplify
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to

and also
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to
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. Your problem should look like:

+

.
Second, find the least common denominator of

and
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to get 9.
Third, make the denominators the same as the least common denominator (LCD). Your problem should look like:

+

.
Fourth, simplify to get the denominators the same. Your problem should look like:

+

.
Fifth, join the denominators. Your problem should look like:

.
Sixth, simplify. Your problem should look like:

, which is the answer.
<em>The </em><em>right</em><em> answer</em><em> is</em><em> </em><em>of </em><em>option</em><em> </em><em>D.</em>
<em>
</em>
<em>In </em><em>the </em><em>given </em><em>graph,</em><em> </em><em>X </em><em>is </em><em>greater </em><em>than </em><em>4</em><em> </em><em>and </em><em>X </em><em>equals </em><em>to </em><em>4</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
Notice that the 2 expressions have 2 common terms.
(r-s) is just (s-r) times (-1)
similarly
(t-s) is just (s-t) times (-1)
this means that :
(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)
the 2 minuses in the first multiplication cancel each other so we have:
-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)
Answer:
d)<span>2(s-r) (t-s) </span>