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2 years ago

Please help ASAP

1 answer:

4 0

It should be multiplied by the opposite of the coefficient of y in the first equation, hence
B)) -2

_____
Actually, it depends on your choice of next step. Multiplying by -2 lets you add the two equations. Multiplying by 2 means you need to subtract one equation from the other. We usually find addition easier, so we would usually choose -2, but either can work. It depends on whether you like to add negative numbers or subtract positive ones.

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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

The number of cakes that maximizes profit is 4.

6 0

2 years ago

BC = Round your answer to the nearest hundredth

stich3 [128]

What am I’m supposed to be looking at

3 0

3 years ago

A monthly contribution of $200 is deposited into an interest-bearing account. If the account has a 4.8% interest rate and compou

Semenov [28]

In 10 years, you will have $31,049.30

7 0

2 years ago

A pet store holds training classes for dogs. The store has two different training programs. The first program charges a $35 memb

GrogVix [38]

The programs cost the same for 7 classes.

Given, no. of classes is represented by c, no. of dogs is represented by d, no. of hours is represented by h, the no. of programs is represented by p and the total cost is represented by t.

The first program charges $35 membership fee and $5 for each class.

The second program charges only $10 for each class.

Now the total cost say $t_{1}$ , for first program can be written in equation form as,

$t_{1} =35+5c$ , here c is the no. of classes.

Similarly, the total cost say $t_{2}$ , for second program can be written in equation form as,

$t_{2} =10c$ .

We have to find out the no. of classes for which the two programs cost the same.

according to the question,

$t_{1} =t_{2}$

$35+5c=10c\\10c-5c=35\\5c=35\\c=7$

Hence for 7 of classes the programs cost the same.

For more details follow the link:

brainly.com/question/4042361

3 0

2 years ago

Read 2 more answers

I need help on this, please hurry and thank you!

inna [77]

Answer:

$A.\ a_n=n^2+1$

Step-by-step explanation:

$Check:$

$a_n=n^2+1\\\\a_1=1^2+1=1+1=2\qquad CORRECT\\\\a_2=2^2+1=4+1=5\qquad CORRECT\\\\a_3=3^2+1=9+1=10\qquad CORRECT\\\\a_4=4^2+1=16+1=17\qquad CORRECT\\\\a_5=5^2+1=25+1=26\qquad CORRECT$

Used PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

First Power, next Addition

4 0

2 years ago

Read 2 more answers