<span>(5+2 i)(4-3i) - (5-2yi)(4-3i)
Factorize out (4 -3i)
(4 -3i)( (5 +2i) - (5 -2yi) )
= </span><span><span>(4 -3i)(5 +2i - 5 + 2yi)</span>
= </span><span><span>(4 -3i)(5 - 5 + 2i + 2yi)</span>
= (4 -3i)(2i + 2yi)
= (4 - 3i)(2 + 2y)i. Let's multiply the first two.
</span>
(4 - 3i)(2 + 2y) = 2*(4 -3i) + 2y*(4 - 3i)
= 8 - 6i + 8y - 6yi
= 8 + 8y - 6i - 6yi
(4 - 3i)(2 + 2y)i = (8 + 8y - 6i - 6yi)i Note: i² = -1
= 8i + 8yi - 6i² - 6yi²
= 8i + 8yi - 6(-1) - 6y(-1)
= 8i + 8yi + 6 + 6y
= 6 + 6y + 8i + 8yi
= (6 + 6y) + (8 + 8y)i In the form a + bi
Answer:
D. y = 12.5x + 15
Step-by-step explanation:
Using the values provided in the table, the only equation that would be valid would be the following...
y = 12.5x + 15
That is because if we substitute any value provided in the table for x , this equation will correctly output the y value shown in the table for the attached x-value. For example, in the table 5 nights (x = 5) should have a total cost of 77.5 (y = 77.5)... Therefore, if we substitute 5 for x in the function it should give us 77.5 which it does.
y = 12.5(5) + 15
y = 62.5 + 15
y = 77.5
Divide both sides by <span>t
</span>
<span>a+b=r/t
</span>Subtract b <span>from both sides
</span>
a<span>=r/t-b = Solution </span>
Answer:2
Step-by-step explanation:
