Answer:
a. 2,9x10⁻⁴ M HCl
Explanation:
A solution is considered acidic when its concentration of H⁺ is higher than 1x10⁻⁷. The higher concentration of H⁺ will be the most acidic solution.
a. 2,9x10⁻⁴ M HCl. In water, this solution dissolves as H⁺ and Cl⁻. That means concentration of H⁺ is 2,9x10⁻⁴ M.
b. 4,5x10⁻⁵M HNO₃. In the same way, concentration of H⁺ is 4,5x10⁻⁵M.
c. 1,0x10⁻⁷M NaCl. As this solution doesn't produce H⁺, the solution is not acidic
d. 1,5x10⁻²M KOH. This solution produce OH⁻. That means the solution is basic nor acidic.
Thus, the solution considered the most acidic is a. 2,9x10⁻⁴ M HCl, because has the higher concentration of H⁺.
I hope it helps!
Answer:
0.550
Explanation:
The absorbance (A) of a substance depends on its concentration (c) according to Beer-Lambert law.
A = ε . <em>l</em> . c
where,
ε: absorptivity of the species
<em>l</em>: optical path length
A 45 mM phosphate solution (solution A) had an absorbance of 1.012.
A = ε . <em>l</em> . c
1.012 = ε . <em>l</em> . 45 mM
ε . <em>l</em> = 0.022 mM⁻¹
We can find the concentration of the second solution using the dilution rule.
C₁ . V₁ = C₂ . V₂
45mM . 11mL = C₂ . 20.0 mL
C₂ = 25 mM
The absorbance of the second solution is:
A = (ε . <em>l</em> ). c
A = (0.022 mM⁻¹) . 25 mM = 0.55 (rounding off to 3 significant figures = 0.550)
Answer:
Sodium is most reactive metal among these. Sodium is present in group one. It is alkali metal.
Explanation:
Please mark as brainliest
When gas molecules condenses, they lose energy.
Answer:
Explanation:
Explanation:
As you know, the empirical formula tells you what the smallest whole number ratio that exists between the atoms that make up a compound is.
In your case, you know that the empirical formula is
NH Cl
2
, which means that the regardles of how many atoms of each element you get in the actual compound, the ratio that exists between them will always be
1:2:1.
What you actually need to determine is how many empirical formulas are needed to get to the molecular formula.
Notice that the problem provides you with the molar mass of the compound. This means that you can use the molar mass of the empirical formula to determine exactly how many atoms you need to form the compound's molecule.
molar mass empirical formula×n=molar mass compound
To get the molar mass of the empirical formula, use the molar masses of its constituent atoms
14.0067 g/mol+2×1.00794 g/mol+35.453 g/mol=51.48 g/mol≈
51.5 g/mol
This means that you have
51.5g/mol×n=51.5g/mol
As you can see, you have
n=1.
This means that the empirical formula and the molecular formula are equivalent,
NH Cl.
2
