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2 years ago

If y’all can answer this I’ll give you’ll some extra points

Chemistry

1 answer:

makvit [3.9K]2 years ago

7 0

Based on the nature ofbthe reaction, entropy (ΔS) increases while enthalpy (ΔH) decreases.

<h3>What are entropy and enthalpy changes?</h3>

Entropy changes, ΔS, refers to change in the degree of the disorderliness of a substance.

When substances become more random, entropy increases and vice versa.

For example, change of state from solid to liquid or gas results in increase in entropy.

Enthalpy changes, ΔH, refers to the changes in heat content of a substance, either a decrease or increase.

Enthalpy is negative when heat is lost and positive ehen heat is gained.

The enthalpy and entropy changes in the given reaction below is as follows:

2CaO(s) + H2O(l) —> 2Ca(OH)2(s)

Entropy, ΔS increases as the substance dissolves in water.

Enthalpy, ΔH, decreases as the substances gives off heat.

Therefore, in the given reaction entropy (ΔS) increases while enthalpy (ΔH) decreases.

Learn more about enthalpy and entropy at: brainly.com/question/1282789

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Give formula for iron (III) oxide

Paraphin [41]

Answer:

Fe2O3

Explanation:

6 0

3 years ago

Read 2 more answers

what is the mass (in grams) of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride?

Gnoma [55]

The mass of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride is 15.26 g.

The balanced chemical reaction is :

2Na + Cl₂ → 2NaCl

Given data :

Mass of sodium = 10.0 g

Number of moles of Na -

Number of moles = Given mass

Molar mass

Number of moles = 10.0 g = 0.43 mol

23 g

Comparing moles of Na and Cl₂ from the balanced chemical equation,

Na : Cl₂

2 : 1

0.43 : 1 x 0.43 = 0.215 mol

Mass of chlorine gas :

(molar mass of chlorine = 71 g)

Mass of chlorine = number of moles x molar mass

Mass = 0.215 mol x 71 g/mol

= 15.26 g

To learn more about sodium and chlorine,

brainly.com/question/14588368

#SPJ4

7 0

1 year ago

I need help, someone please help me

MArishka [77]

Answer:

c) the panda eats both plant and animal: fish and bamboo

d)it shows direction of feeding, the one below is fed on by the one above

6 0

3 years ago

Read 2 more answers

You burn 270 grams of glucose during respiration. How

BlackZzzverrR [31]

Answer:

396 g OF CO2 WILL BE PRODUCED BY 270 g OF GLUCOSE IN A RESPIRATION PROCESS.

Explanation:

To calculate the gram of CO2 produced by burning 270 g of gucose, we first write out the equation for the reaction and equate the two variables involved in the question;

C6H12O6 + 6O2 -------> 6CO2 + 6H2O

1 mole of C6H12O6 reacts to form 6 moles of CO2

Then, calculate the molar mass of the two variables;

Molar mass of glucose = ( 12 *6 + 1* 12 + 16* 6) g/mol = 180 g/mol

Molar mass of CO2 = (12 + 16 *2) g/mol = 44 g/mol

Next is to calculate the mass of glucose and CO2 involved in the reaction by multiplying the molar mass by the number of moles

1* 180 g of glucose yields 6 * 44 g of CO2

180 g of glucose = 264 g of CO2

If 270 g of glucose were to be used, how many grams of CO2 will be produced;

so therefore,

180 g of glucose = 264 g of CO2

270 g of glucose = x grams of CO2

x = 264 * 270 / 180

x = 71 280 / 180

x = 396 g of CO2.

In other words, 396 g of CO2 will be produced by respiration from 270 g of glucose.

8 0

3 years ago

what is the molarity of a solution of hcl if 250 ml of a 0.50 m solution of naoh will completely neutralize 100.ml of this acid

frez [133]

The molarity of the acid is 1.25 M.

Explanation:

We have to find the molarity of HCl by writing the balanced equation that is the neutralization reaction of Hydrochloric acid with the base, Sodium Hydroxide, NaOH.

HCl + NaOH → NaCl + H₂O

From the balanced equation, we can find that one mole of an acid is used to neutralize one mole of a base.

As per the law of volumetric analysis, we can write the equation as,

V1M1 = V2M2

Here V1 and M1 being the volume and molarity of the NaOH

V2 and M2 being the volume and molarity of HCl

V1 = 250 ml

M1 = 0.50 M

V2 = 100 ml

M2 = ?

Now the above equation can be rearranged to find the molarity of the acid as,

M2 = $$\frac{V1M1}{V2}$

= $$\frac{250 ml \times 0.50 M}{100 ml}$

= 1.25 M

So the molarity of the acid is 1.25 M.

4 0

4 years ago