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Brut [27]
2 years ago
13

If y’all can answer this I’ll give you’ll some extra points

Chemistry
1 answer:
makvit [3.9K]2 years ago
7 0

Based on the nature ofbthe reaction, entropy (ΔS) increases while enthalpy (ΔH) decreases.

<h3>What are entropy and enthalpy changes?</h3>

Entropy changes, ΔS, refers to change in the degree of the disorderliness of a substance.

When substances become more random, entropy increases and vice versa.

For example, change of state from solid to liquid or gas results in increase in entropy.

Enthalpy changes, ΔH, refers to the changes in heat content of a substance, either a decrease or increase.

Enthalpy is negative when heat is lost and positive ehen heat is gained.

The enthalpy and entropy changes in the given reaction below is as follows:

2CaO(s) + H2O(l) —> 2Ca(OH)2(s)

Entropy, ΔS increases as the substance dissolves in water.

Enthalpy, ΔH, decreases as the substances gives off heat.

Therefore, in the given reaction entropy (ΔS) increases while enthalpy (ΔH) decreases.

Learn more about enthalpy and entropy at: brainly.com/question/1282789

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Given that the ksp of aipo4 is 9.84 x 10-21 at 25°c, calculate the molar solubility of aiop4
svp [43]
AlPO4----> Al+3 + PO4-3

Ksp= [Al+3] x [PO4-3]= 9.84 x 10^-21

Ksp= (x) (x)= x^2
 
X^2= 9.84x10-21
 
x= 9.92 x 10^-11

The molar solubility is 9.92 x 10^-11
8 0
3 years ago
Read 2 more answers
How many moles of nitrous oxide gas (N2O) is contained in 20.0 L balloon at a pressure of 1.09 atm and a temperature of 298K? Ro
prohojiy [21]

Answer:

There are 0,89 moles of nitrous oxide gas  in the balloon.

Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV= nRT ---> n= PV/RT

n= 1,09 atm x 20,0 L /0.082 l atm / K mol x 298 K

<em>n= 0,89212637 mol</em>

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3 years ago
If you don't keep giving a car gas, the car will eventually stop. *
Strike441 [17]

Answer:

newtons 2nd law is the answer

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3 years ago
Which of the following is part of the molarity equation?
Zinaida [17]
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4 0
2 years ago
Find the volume of hydrogen gas formed when 1.5g of aluminum reacts with aq NaOH at 27 degrees Celcius.
Rudiy27

Answer:

how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?

(A) n=m/M,

n(Al)=5.4/27=0.2 moles

n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles

Number of oxygen atoms= n(O2)*Avogadro's number

=0.15*6.02*10^23=9.03*10^22 oxgyen atoms

(B)

n=m/M

n(Al)=0.6/27=0.02222 moles

n(O2)=n(Al)*3/4=0.016666 moles

m=n*M

m(O2)=0.0166666*32=0.53333 grams

8 0
2 years ago
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