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ludmilkaskok [199]
2 years ago
8

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Chemistry
1 answer:
Mars2501 [29]2 years ago
4 0

Answer:

Thanks

Explanation:

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What is the number of the group that has the most reactive nonmetals (give number and letter- Ex 1A, 2A, etc.)?​
Kryger [21]

Answer:

Group 7A

Explanation:

The group 7A elements consists of the most reactive non-metals on the periodic table.

This group is known as the group of halogens. They consist of element fluorine, chlorine, bromine, iodine and astatine.

  • The elements in this group have the highest electronegativity values.
  • They have 7 valence electrons and requires just one electron to complete their octets.
  • This way, they are highly reactive in their search for that single electron.
3 0
3 years ago
Please help me I can describe a real-world situation in which opposite quantities combine to make zero.
ozzi
A hydrogen atom has 0 charge because its two constituents are oppositely charged; and understand p + q as the number located a distance |q| from p, in the positive or negative direction depending on whether q is positive or negative.
6 0
2 years ago
Read 2 more answers
19. I accidentally mixed bleach and ammonia when cleaning one day. It released 55 liters of deadly chlorine (CI) gas. How many g
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55,000 grams
Hope this helps you out :)
3 0
2 years ago
Draw the products formed from 2-methyl-2-butene by sequences (1.) and (2.). hydroboration followed by oxidation with alkaline hy
nata0808 [166]

Answer:

product won't form hydrogen bond with water

Explanation:

6 0
3 years ago
PLEASE HELP!!!
trasher [3.6K]

Answer:

(a) oxygen

(b) 154g (to 3sf)

(c) 79.9% (to 3sf)

Explanation:

mass (g) = moles × Mr/Ar

note: eqn means chemical equation

(a)

moles of P = 84.1 ÷ 30.973 = 2.7152 moles

moles of O2 = 85÷2(16) = 2.65625 moles

Assuming all the moles of P is used up,

moles of O2 / moles of phosphorus = 5/4 (according to balanced chemical eqn)

moles of O2 required = 5/4 × 2.7152moles = 3.394 moles (more than supplied which is 2.65625moles)

therefore there is insufficient moles of O2 and the limiting reactant is oxygen.

(b)

moles of P2O5 produced

= 2/5 (according to eqn) × 2.7152

= 1.08608moles

mass of P2O5 produced

= 1.08608 × [ 2(30.973) + 5(16) ]

= 154.164g

= approx. 154g to 3 sig. fig.

(c)

% yield = actual/theoretical yield × 100%

= 123/154 × 100%

= 79.870%

= approx. 79.9% (to 3sf)

4 0
2 years ago
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