Answer:
The answer is 18p^3r and 63p^3
Step-by-step explanation:
G.C.F of 18p^3 r and 45p^4q is = 9p^3
18p^3r = 2*3*3*p*p*p*r
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
G.C.F of 63p^3 and 45p^4q is = 9p^3
63p^3 = 3*3*7*p*p*p
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
Therefore the answer is 18p^3r and 63p^3....
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Answer:
m = 5,520.619
Step-by-step explanation:
The given equation is :
y=5,520.619x-1,091.393 ....(1)
The general form of equation is given by :
y = mx +c ...(2)
Where
m is slope of line
c is y-intercept
Comparing equation (1) and (2), we get :
Slope, m = 5,520.619
Hence, the slope of the given line is 5,520.619.
9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
