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Veseljchak [2.6K]
4 years ago
7

A manometer connected to a Pitot-static tube has a difference in the height of the two columns of water of 10 cm when the Pitot-

static tube is placed in a flow of air at standard sea level conditions. What is the velocity of the airflow
Engineering
1 answer:
kaheart [24]4 years ago
7 0

Answer:

v = 40 m/s

Explanation:

Difference in the height of the two columns:

h_m = \triangle h = 10 cm \\h_m = 0.1 m

Air density, \rho_{air} = 1.225 kg/m^3

Water density, \rho_{w} = 1000 kg/m^3

The velocity of air flow is given by the equation:

v =  \sqrt{2gh_m (\frac{p_w}{p_{air}} - 1) } \\\\v =  \sqrt{2*9.81*0.1 (\frac{1000}{1.225} - 1) }\\\\v = 40 m/s

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