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sineoko [7]
3 years ago
9

Two technicians are discussing a vehicle that will not start. Tech A states that a problem with the immobilizer system may be th

e cause. Tech B states that an open in the starter relay may be the cause. Which technician is correct?
Engineering
1 answer:
Anestetic [448]3 years ago
3 0
Technician B.

Explanation:

The starter motor is what turns the engine, until enough electricity is generated with momentum to keep the engine running and cycling. If there is a problem with the immobilizer, the engine may shake or come off the mount at higher RPMs, however, will not have any problems initially starting the engine. The starter is most important for starting the engine, therefore, Technician B is correct In this case.
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Drag the tiles to the correct boxes to complete the pairs.
sammy [17]

Explanation:

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wireless technology: transistor

7 0
2 years ago
HELP PLEASE!! ASAP!!!!
dezoksy [38]

Actions violated:

  • Long hair isn't tied up
  • The girl isn't wearing a lab coat
  • The girl isn't wearing safety goggles
  • Extra: There doesn't seem to be an emergency fire blanket in the safe

Actions to be taken:

  • Make sure the girl wears a lab coat or kick her out
  • Make sure the girl wears safety goggles or kick her out
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Edit: Use these to write your paragraph.

5 0
3 years ago
Read 2 more answers
Refrigerant-134a at 400 psia has a specific volume of 0.1144 ft3/lbm. Determine the temperature of the refrigerant based on (a)
vekshin1

Answer:

a) Using Ideal gas Equation, T = 434.98°R = 435°R

b) Using Van Der Waal's Equation, T = 637.32°R = 637°R

c) T obtained from the refrigerant tables at P = 400 psia and v = 0.1144 ft³/lbm is T = 559.67°R = 560°R

Explanation:

a) Ideal gas Equation

PV = mRT

T = PV/mR

P = pressure = 400 psia

V/m = specific volume = 0.1144 ft³/lbm

R = gas constant = 0.1052 psia.ft³/lbm.°R

T = 400 × 0.1144/0.1052 = 434.98 °R

b) Van Der Waal's Equation

T = (1/R) (P + (a/v²)) (v - b)

a = Van Der Waal's constant = (27R²(T꜀ᵣ)²)/(64P꜀ᵣ)

R = 0.1052 psia.ft³/lbm.°R

T꜀ᵣ = critical temperature for refrigerant-134a (from the refrigerant tables) = 673.6°R

P꜀ᵣ = critical pressure for refrigerant-134a (from the refrigerant tables) = 588.7 psia

a = (27 × 0.1052² × 673.6²)/(64 × 588.7)

a = 3.596 ft⁶.psia/lbm²

b = (RT꜀ᵣ)/8P꜀ᵣ

b = (0.1052 × 673.6)/(8 × 588.7) = 0.01504 ft³/lbm

T = (1/0.1052) (400 + (3.596/0.1144²) (0.1144 - 0.01504) = 637.32°R

c) The temperature for the refrigerant-134a as obtained from the refrigerant tables at P = 400 psia and v = 0.1144 ft³/lbm is

T = 100°F = 559.67°R

7 0
3 years ago
Driving alone without the distraction from passengers reduces the risks you face in driving.
vredina [299]

Driving alone without the distraction from passengers reduces the risks you face in driving.

True

3 0
2 years ago
A good rule of thumb is to design the horizontal stabilizer so that its area is about 1/6 to 1/8 of the area of the wing. If the
erik [133]

Answer:

Stabilizer with area = 14 cm2

Explanation:

i dont know why but its right

4 0
3 years ago
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