Thermoplastics burn upon heating. a)-True b)- false?

If gas costs $3.50 per gallon, how much would it cost to drive 500 miles in a city in a car that is 58.3 km/L

Akimi4 [234]

1 liter = .264 gallon
1 km = .621 mile

this means that 58.3km/L is equal to 137.13mpg

so

500/137.13 = 3.65 gallons of gas

3.65 x 3.5 = $12.78

5 0

2 years ago

Do NOT mix ____________________ with used oil. A) Transmission oilB) AntifreezeC) Hydraulic fluidsD) Synthetic oil

Scorpion4ik [409]

Do not mix Antifreeze with used oil

6 0

3 years ago

A dryer is shaped like a long semi-cylindrical duct of diameter 1.5 m. The base of the dryer is occupied with water-soaked mater

Anestetic [448]

Answer:

0.0371 kg/s.m

Explanation:

From the given information, let's have an imaginative view of the semi-cylinder; (The image is shown below)

Assuming the base surface of both ends of the cylinder is denoted by:

$A_1 \ and \ A_2$

Thus, using the summation rule, the view factor $F_{11$ and $F_{12$ is as follows:

$F_{11}+F_{12}=1$

Let assume the surface (1) is flat, the $F_{11} = 0$

Now:

$0+F_{12}=1$

$F_{12}=1$

However, using the reciprocity rule to determine the view factor from the dome-shaped cylinder $A_2$ to the flat base surface $A_1$ ; we have:

$A_2F_{21} = A_{1}F_{12} \\ \\ F_{21} = \dfrac{A_1}{A_2}F_{12}$

Suppose, we replace DL for $A_1$ and

$A_2$ = $\dfrac{\pi D}{2}$

Then:

$F_{21} = \dfrac{DL}{(\dfrac{\pi D}{2}) L} \times 1 \\ \\ =\dfrac{2}{\pi} \\ \\ =0.64$

Now, we need to employ the use of energy balance formula to the dryer.

i.e.

$Q_{21} = Q_{evaporation}$

But, before that; let's find the radian heat exchange occurring among the dome and the flat base surface:

$Q_{21}= F_{21} A_2 \sigma (T_2^4-T_1^4) \\ \\ Q_{21} = F_{21} \times \dfrac{\pi D}{2} \sigma (T_2^4 -T_1^4)$

where;

$\sigma = Stefan \ Boltzmann's \ constant$

$T_1 = base \ temperature$

$T_2 = temperature \ of \ the \ dome$

∴

$Q_{21} = 0.64 \times (\dfrac{\pi}{2}\times 1.5) \times 5.67 \times 10^4 \times (1000^4 -370^4)\\ \\ Q_{21} = 83899.15 \ W/m$

Recall the energy balance formula;

$Q_{21} = Q_{evaporation}$

where;

$Q_{evaporation} = mh_{fg}$

here;

$h_{fg}$ = enthalpy of vaporization

m = the water mass flow rate

∴

$83899.15 = m \times 2257 \times 10^3 \\ \\ m = \dfrac{83899.15}{ 2257 \times 10^3 }\\ \\ \mathbf{m = 0.0371 \ kg/s.m}$

6 0

2 years ago

Consider a single crystal of silver oriented such that a tensile stress is applied along a [001] direction. If slip occurs on a

Alika [10]

Answer:

The answer is 0.4490Mpa

Explanation:

Given :

P in direction of 001 , P = 1.1MPa

slip plane = 111, slip plane normal direction of 111,

slip direction = 101

$T_{R}$ = δcosФcosλ

= (001 * 101) = 1 = $\sqrt{2}$ cosλ

(111 * 001) 1 $\sqrt{3}$ cosФ

= 1.1 MPa * $\frac{1}{\sqrt{2} }$ * $\frac{1}{\sqrt{3} }$

1.1 Mpa * 1/1.4142 * 1/1.7320

1.1 Mpa * 0.7072 * 0.5773

= 0.4490 MPa

therefore the resolved shear stress = 0.4490MPa

7 0

2 years ago

Describe the steps involved in accomplishing a life-cycle cost analysis (LCCA). I have listed the steps. just describe. a)-Opera

Tasya [4]

Explanation:

a). Operational Performance

It is defined as the parameter that describes the percentage of accuracy of performing an operation or carrying out an activity.

b). Salvage externalities

Salvage in Life cycle cost analysis is a process of estimating the value of the remaining assets in the organisation,.

c). Value Vs Risk

When we take risk in doing any activity we know the value of accomplising the activity. So value relates directly with risk. When the value of a certain task is high, the risk involve in it is also high.

d). Initial expenditure

Initial expenditure is nothing but the cost involve in starting a particular acitvity or task at the starting phase.

e). Maintenance implications

It lays emphasis in maintaining the cost of every possible parameters that are involve in the activity. It includes labour, machines, positions, energy, facilities, etc.

8 0

3 years ago