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denis23 [38]
3 years ago
14

Thermoplastics burn upon heating. a)-True b)- false?

Engineering
1 answer:
miv72 [106K]3 years ago
4 0

Yes, It is indeed true that Thermoplastics and thermosettingplastics burn upon heating.

You might be interested in
Component of earthing and reasons why each material is being used<br><br>​
timofeeve [1]

Answer:

The components of earthing are Earth electrode, Main earthing terminals/bars, Earthing conductors, Protective conductors Equipontential binding conductors and Electrically independent electrodes.

3 0
2 years ago
A pressure gage at the inlet to a gas compressor indicates that the gage pressure is 40.0 kPa. Atmospheric pressure is 1.01 bar.
bonufazy [111]

Answer:

Given

inlet Pga =40kpa = 40000pa

Patm=1.01bar = 1.01 x 100000pa =101000pa

exit Pab= 6.5 (inlet Pab)

But generally, Pab = Patm + Pga

1. the absolute pressure of the gas at the inlet, inlet Pab?

inlet Pab = Patm + inlet Pga

            = 101000pa + 40000pa = 141kpa

the absolute pressure of the gas at the inlet, inlet Pab = 141kpa

2. the gage pressure of the gas at the exit? exit Pga?

exit Pab = Patm + exit Pga

exit Pga = exit Pab - Patm

             = (6.5 x 141kpa) - 101kpa

              = 815.5kpa

the gage pressure of the gas at the exit exit Pga=815.5kpa

5 0
3 years ago
A block of ice weighing 20 lb is taken from the freezer where it was stored at -15"F. How many Btu of heat will be required to c
Rus_ich [418]

Answer:

Heat required =7126.58 Btu.

Explanation:

Given that

Mass m=20 lb

We know that

1 lb =0.45 kg

So 20 lb=9 kg

m=9 kg

Ice at -15° F and we have to covert it at 200° F.

First ice will take sensible heat at up to 32 F then it will take latent heat at constant temperature and temperature will remain 32 F.After that it will convert in water and water will take sensible heat and reach at 200 F.

We know that

Specific heat for ice C_p=2.03\ KJ/kg.K

Latent heat for ice H=336 KJ/kg

Specific heat for ice C_p=4.187\ KJ/kg.K

We know that sensible heat given as

Q=mC_p\Delta T

Heat for -15F to 32 F:

Q=mC_p\Delta T

Q=9\times 2.03(32+15) KJ

Q=858.69 KJ

Heat for 32 Fto 200 F:

Q=mC_p\Delta T

Q=9\times 4.187(200-32) KJ

Q=6330.74 KJ

Total heat=858.69 + 336 +6330.74 KJ

Total heat=7525.43 KJ

We know that 1 KJ=0.947 Btu

So   7525.43 KJ=7126.58 Btu

So heat required to covert ice into water is 7126.58 Btu.

8 0
3 years ago
A bridge to be fabricated of steel girders is designed to be 500 m long and 12 m wide at ambient temperature (assumed 20°C). Exp
Volgvan

Answer:

a) 22.5number

b) 22.22 m length

Explanation:

Given data:

Bridge length = 500 m

width of bridge = 12 m

Maximum temperature = 40 degree C

minimum temperature  = - 35 degree C

Maximum expansion can be determined as

\Delta L = L \alpha (T_{max} - T_{min})

where , \alpha is expansion coefficient = 12\times 10^{-6} degree C

SO, \Delta L = 500\times 12\times 10^{-6}\times ( 40 - (-35))

\Delta L = 0.45 m = 450 mm

number of minimum expansion joints is calculated as

n = \frac{450}{20} = 22.5

b) length of each bridge

Length = \frac{500}{22.5} = 22.22 m

8 0
2 years ago
Multiply. Write the answer in simplest form. 1 3/10×1/8
kicyunya [14]

9514 1404 393

Answer:

  13/80

Explanation:

The product is ...

  (1 3/10)×(1/8) = (13/10)×(1/8) = (13×1)/(10×8) = 13/80

4 0
2 years ago
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