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Kazeer [188]
3 years ago
14

Two players find themselves in a legal battle over a patent. The patent is worth 20 for each player, so the winner would receive

20 and the loser 0. Given the norms of the country they are in, it is common to bribe the judge of a case. Each player can secretly oer a bribe of 0, 9 or 20, and the one whose bribe is the largest is awarded the patent. If both choose not to bribe, or if the bribes are the same amount, then each has an equal chance of being awarded the patent. (If a player decides to bribe then the judge pockets it regardless of who gets the patent).
(a) Derive the game matrix.

(b) Is the game dominance solvable? If so, findnd the strategy prole surviving IDSDS.

(c) Now consider the case in which the allowed bribe amounts are instead 0, 9 and 15. Is the game dominance solvable? Find the best responses of each player to each of the pure strategies of the opponent.

Engineering
1 answer:
Alborosie3 years ago
5 0

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

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Steam undergoes an isentropic compression in an insulated piston–cylinder assembly from an initial state where T1 5 1208C, p1 5
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Answer:

temperature T2 = 826.9°C

\frac{W}{m} = -1142.7 kJ/kg

Explanation:

given data

initial state temperature = 120°C

final state pressure p1 = 1 bar

pressure p2 =  100 bar

solution

we use here super heated water table A6 that is

specific internal energy u1 = 2537.3 kJ/kg

specific entropy s1 = 7.4668 kJ/kg.K

and

here specific entropy stage 1 = stage 2

so for specific entropy and pressure 100 bar

specific internal energy u2 = 3680 kJ/kg

and temperature T2 = 826.9°C

so here now we get specific work of steam is

ΔU = -W     ...........1

m ( u1 - u2) = W

\frac{W}{m} = u1 - u2

\frac{W}{m} = 2537.3 - 3680

\frac{W}{m} = -1142.7 kJ/kg

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For two different air velocities, the Nusselt number for two different diameter cylinders in cross flow is the same. The average
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C smaller than that of the larger-diameter cylinder
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The yield of a chemical process is being studied.The two most important variables are thought to be the pressure and the tempera
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Answer:

<u>note:</u>

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3 years ago
Lance is the sitting judge in the local family court. What education might have been
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The pressure gage on a 2.5-m^3 oxygen tank reads 500 kPa. Determine the amount of oxygen in the tank if the temperature is 28°C
s2008m [1.1K]

Answer:

19063.6051 g

Explanation:

Pressure = Atmospheric pressure + Gauge Pressure

Atmospheric pressure = 97 kPa

Gauge pressure = 500 kPa

Total pressure = 500 + 97 kPa = 597 kPa

Also, P (kPa) = 1/101.325  P(atm)

Pressure = 5.89193 atm

Volume = 2.5 m³ = 2500 L ( As m³ = 1000 L)

Temperature = 28 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (28.2 + 273.15) K = 301.15 K  

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

5.89193 atm × 2500 L = n × 0.0821 L.atm/K.mol × 301.15 K  

⇒n = 595.76 moles

Molar mass of oxygen gas = 31.9988 g/mol

Mass = Moles * Molar mass = 595.76 * 31.9988 g = 19063.6051 g

7 0
3 years ago
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