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2 years ago

5

What is the slope of the line that passes through the points (–2, 5) and (1, 11)?

2 answers:

Ket [755]2 years ago

6 0

Hello!

Step-by-step explanation:

Slope: $\frac{Y^2-Y^1}{X^2-X^1}=\frac{rise}{run}$

$\frac{11-5=6}{1-(-2)=1+2=3}=\frac{6}{3}=2$

<u><em>Slope is 2.</em></u>

<u><em>Answer is 2.</em></u>

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

Bess [88]2 years ago

3 0

$Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{11-5}{1-(-2)} = \frac{6}{1+2} = \frac{6}{3} = \boxed{\bf{2}}$

The answer is B) 2.

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Papa johns has a pizza whose circumference is 16 Pi. What is the area of the pizza

gulaghasi [49]

The area of the pizza is <span>20.37.

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8 0

2 years ago

Solve 2x2 + 20x = −38. (1 point)

RoseWind [281]

Answer:

The solutions are $x=-5+\sqrt{6}$ and $x=-5-\sqrt{6}$

Step-by-step explanation:

we have

$2x^{2} +20x=-38$

Divide by $2$ both sides

$x^{2} +10x=-19$ ------> $x^{2} +10x+19=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +10x+19=0$

so

$a=1\\b=10\\c=19$

substitute

$x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}$

$x=\frac{-10(+/-)\sqrt{100-76}}{2}$

$x=\frac{-10(+/-)\sqrt{24}}{2}$

$x=\frac{-10(+/-)2\sqrt{6}}{2}$

$x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}$

$x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}$

8 0

2 years ago

Read 2 more answers

3/4 x 10 = ? <br> thank you!!!

lesantik [10]

3/4 *10 is 7.5. 0.75 * 10 = 7.5

4 0

2 years ago

Read 2 more answers

Round off the following numbers to two decimal places <br> 1.2.1) 0,77677<br> 1.2.2) 34,2784682

andre [41]

1) 0.78
2) 34.28
This is because the number in the 3rd decimal place for both numbers is 5 or above so it is rounded up rather than down.

8 0

3 years ago

PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK

Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

$\sf \cos(\theta)=\dfrac{A}{H}$

where:

$\theta$ is the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Given:

$\theta$ = ∠KLM
A = LN = 8
H = KL = 15.2

$\implies \sf \cos(KLM)=\dfrac{8}{15.2}$

$\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)$

$\implies \sf \angle KLM=58.24313614^{\circ}$

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}$

Given:

r = 15.2
∠KLM = 58.24313614°

$\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)$

$\implies \textsf{Arc length MK}=\sf 15.45132428\:units$

6 0

2 years ago