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Sonbull [250]
4 years ago
13

Which equation can be used to find the answer? Sharifa spends $51 on the first day of her vacation. This leaves her with $127 to

spend during the rest of her vacation. How much money did Sharifa bring to spend during her vacation?
A. t = 127 · 2 t = 254 $254

B. t – 51 = 127 t = 178 $178

C. t + 51 = 127 t = 76 $76

D. t = 127 ÷ 2 t = 63.5 $63.50
Mathematics
1 answer:
Dima020 [189]4 years ago
6 0
<span>The answer to this problem is B. t – 51 = 127 t = 178 $178.</span>
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Does anybody know this one? 40= 15 - 9x- 2
asambeis [7]

Step-by-step explanation:

Simplifying 40 = 15 + -9x + -2

Reorder the terms: 40 = 15 + -2 + -9x

Combine like terms: 15 + -2 = 13 40 = 13 + -9x

Solving 40 = 13 + -9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9x' to each side of the equation. 40 + 9x = 13 + -9x + 9x

Combine like terms: -9x + 9x = 0 40 + 9x = 13 + 0 40 + 9x = 13

Add '-40' to each side of the equation. 40 + -40 + 9x = 13 + -40

Combine like terms: 40 + -40 = 0 0 + 9x = 13 + -40 9x = 13 + -40

Combine like terms: 13 + -40 = -27 9x = -27

Divide each side by '9'. x = -3

Simplifying x = -3

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3 years ago
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What is the opposite of 1?
Verizon [17]
The opposite of 1 is -1 :)
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3 years ago
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What is 11 divided by 4?
PtichkaEL [24]

Answer:2.75 or 11/4

Step-by-step explanation:

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3 years ago
Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
4 years ago
Find the distance between (3,7) and (8,7)
choli [55]

Answer:

5

Step-by-step explanation:

d = 5

For:

(X1, Y1) = (3, 7)

(X2, Y2) = (8, 7)

Distance Equation Solution:

d=(8−3)2+(7−7)2−−−−−−−−−−−−−−−√d=(8−3)2+(7−7)2

d=(5)2+(0)2−−−−−−−−−√d=(5)2+(0)2

d=25+0−−−−−√d=25+0

d=2–√5d=25

d=5

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3 years ago
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