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Kobotan [32]
3 years ago
6

A line has the equation 3x-2y=6, any line parallel to this line has slope (?)

Mathematics
1 answer:
vitfil [10]3 years ago
5 0

Answer:

Slope is 3/2

Step-by-step explanation:

3x-2y=6

-2y=-3x+6

y=3/2-3

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Which expression is equivalent to square root 55x^7y6/11x^11y^8
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Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

6 0
3 years ago
Suppose triangle ABC will be dilated using the rule . What will be the distance from the center of dilation, Q, to the image of
Blababa [14]

Answer:

4

Step-by-step explanation:

The rule of dilation is D_{Q,\frac{2}{3}}. This means that each distance QX' is equal to \dfrac{2}{3}QX, where X is initial point and X' is its image after dilation.

Since QA=6, then

QA'=\dfrac{2}{3}\cdot 6=4.

6 0
3 years ago
Read 2 more answers
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