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user100 [1]
3 years ago
13

Are ultrasound waves high energy waves or low energy waves?

Physics
1 answer:
german3 years ago
3 0
And think they are high energy waves. But I'm not sure
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yellow cab taxi charges a $1.75 flat rate in addition to $0.65 per mile. kim has no more than $10 to spend on a ride. how many m
Nat2105 [25]

Answer:

you could go 12 miles paying $7.80 and $1.75

So in total being $9.55

5 0
2 years ago
Ohm’s Law is represented by the equation I=V/R. Explain how the current would change if the amount of resistance decreased and t
vesna_86 [32]

Answer:

The current will increase with reduction in the resistance.

Explanation:

Electrical resistance reduces the flow of electricity through a conductor just like friction reduces our speed. The higher the resistance the harder it will be for the current to flow and vice versa, hence, higher resistance produces a smaller current if the voltage is held constant. The voltage is the electrical drive.

3 0
3 years ago
Read 2 more answers
What is the wavelength of a wave that has a speed of 350 meters/second and a frequency of 140 hertz?
sergey [27]

Answer:2.5m

Explanation:

3 0
2 years ago
If you walk a distance of 8 blocks and then 3 blocks south from home, what is your position compared to home? What distance did
Harman [31]

The position compared to that of home is a reference to displacement, I believe.

Displacement = x total - x initial

So I believe the answer is 5 blocks due north (if you’re walking linearly from your home), unless the questions is referring to relative displacement, in which then you’d need to use the Pythagorean theorem to find the hypotenuse between both positions. And then you’d have to find theta for the degrees between the south direction and the other unmentioned direction. But I don’t think that’s the case.

Distance refers to x total and doesn’t care for direction, as this refers to a scalar quantity opposed to a vector. Thus the equation is just

d = x

So 8 blocks + 3 blocks = a distance of eleven blocks walked total

7 0
3 years ago
You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that
loris [4]

Questions Diagram is attached below

Answer:

T=2.08s

Explanation:

From the question we are told that:

Speed of Train V=3.0m.s

Angle \theta=12\textdegree

Height of window h_w=0.90m

Width of window w_w=2.0m

The Horizontal distance between B and A from Trigonometric Laws is mathematically given by

 b=\frac{0.9}{tan12}

 b=4.23

Therefore

Distance from A-A

 d_a=2.0+4.23

 d_a=6.23

Therefore

Time Required to travel trough d is mathematically given as

 T=\frac{d_a}{v}

 T=\frac{6.23}{3}

 T=2.08s

5 0
3 years ago
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