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2 years ago

What intermolecular force is responsible for the attraction between an ion and a polar molecule?

Physics

1 answer:

Pani-rosa [81]2 years ago

8 0

Answer:

Dipole ion forces

Explanation:

Dipole ion forces are attractive forces between an ion (an atom that has lost or gained an electron, so it has a charge) and a polar molecule. A molecule is a dipole when there is an asymmetric distribution of electrons because the molecule is made up of atoms of different electronegativity. The ion then attaches to the part of the molecule that has its opposite charge: the positive end of the polar molecule faces the anion (negatively charged ion) and the negative end of the polar molecule faces the cation ( positively charged ion).

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What happens to the force attraction of the distance two objects is increased?

Fed [463]

Answer:

Explanation:

The attraction weakens. Two objects that are farther apart are not drawn together as strongly as if they were close together.

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2 years ago

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11 months ago

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The length of your eye decreases slightly as you age, making the lens a bit closer to the retina. Suppose a man had his vision s

julia-pushkina [17]

Answer:

<h2>A. Nearsightedness</h2>

Explanation:

A nearsightedness is an eye defect that occurs when someone is only able to see close ranged object but not far distance object. According to the question, if the length of my eye decreases slightly as I age, this means there is a possibility that I will find it difficult to view a far distance object as I age.

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2 years ago

A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end just bef

stich3 [128]

Answer:

v = 7.67 m/s for L= 1m

Explanation:

Let's use the conservation of mechanical energy, at the highest point and the lowest point

Initial. Vertical ruler

Em₀ = mg h

Final. Just before touching the floor

$Em_{f}$ = K = ½ I w²

Em₀ = $Em_{f}$

m g h = ½ I w²

The moment of inertia of a ruler that turns on one end is

I = 1/3 m L²

Let's replace

m g h = ½ (1/3 m L²) w²2

g h = 1/6 L² w²

They ask for the speed of the end so the height h is equal to the length of the ruler

g L = 1/6 L² w²

The linear and angular variables are related

v = w r

w = v / r

In this case the point of interest a in strangers r = L

g L = 1/6 L² v² / L²

v = √ 6 g L

Let's calculate

Assume that the length of the meter is L = 1 m

v = √ (6 9.8 1)

v = 7.67 m/s

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2 years ago

It took 50 joules to push a crate 2.5 meters. With what force was the crate pushed?

Inga [223]

It took 50 joules to push a crate 2.5 meters. With what force was the crate pushed?

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1 year ago